Answer:
Solution: x = -2; y = 3 or (-2, 3)
Step-by-step explanation:
<u>Equation 1:</u> y = -5x - 7
<u>Equation 2:</u> -4x - 3y = -1
Substitute the value of y in Equation 1 into the Equation 2:
-4x - 3(-5x - 7) = -1
-4x +15x + 21 = -1
Combine like terms:
11x + 21 = - 1
Subtract 21 from both sides:
11x + 21 - 21 = - 1 - 21
11x = -22
Divide both sides by 11 to solve for x:
11x/11 = -22/11
x = -2
Now that we have the value for x, substitute x = 2 into Equation 2 to solve for y:
-4x - 3y = -1
-4(-2) - 3y = -1
8 - 3y = -1
Subtract 8 from both sides:
8 - 8 - 3y = -1 - 8
-3y = -9
Divide both sides by -3 to solve for y:
-3y/-3 = -9/-3
y = 3
Therefore, the solution to the given systems of linear equations is:
x = -2; y = 3 or (-2, 3)
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Given:
7 red candies
9 blue candies
12 pink candies
Condition:
Number of bags that has equal number of candies.
We can do 7 bags with 1 colored candy each. There will be an excess of 2 blue candies and 5 pink candies.
We can do 4 bags with 1 red candy, 2 blue candies, 3 pink candies. There will be an excess of 3 red candies and 1 blue candy.
We can do 3 bags with 2 red candies, 3 blue candies, 4 pink candies. There will be an excess of 1 red candy.
Answer:
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
Step-by-step explanation:
Let the age of Alicia be x
Let the age of Quentin be y
Let the age of Rosalyn be z
If the sum of the siblings’ ages, in years, is 48 then;
x+y+z = 48.... 1
If Rosalyn is two years older than Quentin then;
z =y+2 ..... 2
Also if Quentin is four years younger than Alicia then;
y = x-4 ... 3
From 3:
x = y+4 ... 4
Substitute 2 and 4 into 1 to have:
y+4+y+y+2 = 48
3y + 6= 48
3y = 48-6
3y= 42
y = 14
Since x= y+4
x = 14+4
x = 18
Since z = y+2
z = 14+2
z = 16year
This means that;
Alicia is 18years
Quentin is 14years
Rosalyn is 16years
Answer: x=2 and y=-3
Step-by-step explanation: you’re welcome
18.9 rounded is 19
5.2 rounded is 5
19 * 5 = 95
