Question

The temperature of a 6.0-g sample of glass changed from 20c to 45c when it absorbed 550 j of heat. What is the specific heat of this glass sample

Answer 1

Answer: $3.33J/g^oC$

Explanation:

$Q= m\times c\times \Delta T$

Q= heat gained  = 550 J

m = mass of the substance = 6.0 g

c = heat capacity of  iron = ?    

$\Delta T={\text{Change in temperature}}=(45-20)^oC=25^0C$  

$500J=6.0g\times c\times 25^oC$

$c= 3.33J/g^oC$

Thus specific heat of the glass sample is $3.33J/g^oC$