Answer: The equilibrium constant for the reaction at 25 °C is 346.7
Explanation:
Formula used :
where,
= standard Gibb's free energy change = -14.50kJ/mol =14500 J/mol
R = universal gas constant = 8.314 J/K/mole
T = temperature =
= equilibrium constant = ?
Putting in the values we get:
The equilibrium constant for the reaction at 25 °C is 346.7
Answer: A. The reaction takes place in one step.
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
Molecularity of the reaction is defined as the number of atoms, ions or molecules that must colloid with one another simultaneously so as to result into a chemical reaction.
Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.
Elementary reactions are defined as the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical reaction.
k= rate constant
a= order with respect to A
b = order with respect to B
Answer:
2.
3.
Explanation:
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2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:
Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:
Therefore, we plug in the given data to obtain:
3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:
Therefore, we plug in the data to obtain:
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Answer:
Explanation:
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In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:
Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:
Then, we solve for specific heat of the metallic alloy to obtain:
Thereby, we plug in the given data to obtain:
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