Answer:
7 mol Fe
General Formulas and Concepts:
<u>Chemistry</u>
Explanation:
<u>Step 1: Define</u>
RxN: Zn (s) + FeSO₄ (aq) → ZnSO₄ (aq) + Fe (s)
Given: 7 moles Zn
<u>Step 2: Stoichiometry</u>
<u />
= 7 mol Fe
<u>Step 3: Check</u>
<em>We are given 1 sig fig.</em>
Since our final answer is in 1 sig fig, there is no need to round.
Answer:
a, d and e. are true.
Explanation:
The reaction that occurs is:
Na2CO3(aq) + CaCl2(aq) → CaCO3(s) + 2NaCl
In ideal conditions, the percent yield of the reaction must be 100%. All explanations about why the student could not collect all precipitate are right:
a. The combined reactants were not stirred before filtering the precipitate. Not stirring could not promote all the reaction. <em>TRUE.</em>
b. The student did not completely dry the precipitate before weighing it. If the student don't dry the precipitate, the mass of precipitate must be higher producing a percent yield > 100%. <em>FALSE.</em>
c. The precipitate was not washed prior to drying. Produce more mass. <em>FALSE.</em>
d. A rubber policeman was not used to scrape precipitate from the beaker. If the student doesn't collect all the precipitate the percent yield could be < 100%.. <em>TRUE.</em>
e. The filter paper was not wetted with water prior to filtering the precipitate. <em>TRUE. </em>If you don't wet the filter paper you can lose a part of precipitate from the walls of this one.
Answer:
2.7 x 10^-1
Explanation:
The places you move to the left are added to the 10 in negative exponential
K will always have an oxidation state of +1. Now O is -2 except in peroxides, this is not a peroxide, so total charge will be -6, if you subtract the +1 of K from it, it leaves -5 charge to be neutralized by Cl in KClO3, so Cl will be +5. In the product side, K will still have the same oxdiation which is +1 and Cl would have -1. O2 will have zero. <span>Now, Cl is gaining the electrons to go from +5 to -1, so it is getting reduced while O2 is losing electrons to go from -2 to zero so it is getting oxidized.</span>
