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zaharov [31]
3 years ago
15

22.00 g of CO2 has a volume of 50.00 L and a pressure of 0.8210 atm. What must be the

Chemistry
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

T = 9.875K

Explanation:

The ideal gas Law is PV = nRT.

P = Pressure

V = Volume

n = amount of substance

R =  8.314 J/(K. mol)

T = Temperature in Kelvin

22g CO2

CO2 Molar Mass = 44g/mol

C = 12g/mol

O = 16g/mol

P = 0.8210atm

V = 50L

PV = nRT

0.8210 x 50 = 8.314 x 0.5 x T

41.05 =  4.157T

T = 41.05/4.157

T = 9.875K

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3 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
3 years ago
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