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german
4 years ago
9

How many moles of NaCl (s) can be formed from 32 moles of Cl2 (g) reacting with an excess of Na (s)?

Chemistry
1 answer:
blagie [28]4 years ago
7 0

Answer:

64 moles

Explanation:

Let us begin by writing a balanced equation for the reaction. This is illustrated below:

2Na + Cl2 —> 2NaCl

From the equation above,

1 mole of Cl produced 2 moles of NaCl.

Therefore, 32 moles of Cl will produce = 32 x 2 = 64 moles of NaCl.

Therefore, 64 moles of NaCl are produced

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How many grams are in 2.54 x 10^23 molecules of CO2
Ivan

Answer:

=<em><u> 0.42 moles of CO2 </u></em>

Explanation:

From Avogadro's constant

6.02×10^23 molecules are in 1 mole of CO2

2.54×10^23 molecules will be in

=[(2.54×10^23) ÷ (6.02×10^23)]

= 0.42 moles of CO2

8 0
3 years ago
How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
tresset_1 [31]

Answer: 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of AlCl_{3} and \frac{9}{2} moles of H_{2}.

The reaction equation now will be as follows.

3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}

The moles \frac{9}{2} can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

6 0
3 years ago
Which of the following pairs of elements is most likely to form an ionic compound?
Scrat [10]

Explanation:

magnesium and sodium because they are minerals and part of iron

5 0
3 years ago
If cacl2 is dissolved in water, what can be said about the concentration of the ca2+ ion? view available hint(s) if is dissolved
Simora [160]
The concentration of Ca2+ ions is half that of the Cl- ions.
8 0
3 years ago
Read 2 more answers
What is the name of the compound BrF
Rashid [163]

Bromine


hope that helps :)

7 0
3 years ago
Read 2 more answers
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