Answer:
the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
Step-by-step explanation:
Given the data in the question;
μ_x = 10 pound bags
standard deviation s_x = 0.24 pounds
sample size n = 4
The bag weights are normally distributed so;
p( x' less than 9.8 ) will be;
p( (x'-μ_x' / s_x') < (9.8-μ_x' / s_x') )
we know that;
μ_x' = μ_x = 10
and s_x' = s_x/√n = 0.24/√4
so; we substitute
p( z < ( (9.8 - 10) / (0.24/√4) )
p( z < -0.2 / 0.12 )
p( z < -1.67 )
{ From z-table }
⇒ p( z < -1.67 ) = 0.0475 ≈ 0.05
Therefore, the probability that a sample of 4 bags will have a mean weight less than 9.8 pounds is 0.05
D
hope this helps
this is because the .3 is repeating but it is the same number repeating(it is a pattern)
Answer:
See below
Step-by-step explanation:
1. 11^2
2. No
3. 18^2
4. 4^2
5. 9^2
6. No
7. 20^2
8. No
9. 15^2
Hope that helps! :)
We are given with two distances: 5,880,000,000,000 miles and 15.8 light-years. we convert first the light-years distance through the speed of light : 3 x 108 m/s. v = d/t; d = 3x10 8 m/s * 15.8 light years * 31536000 s = 1.4948 x1017 m = 9.28829 x 1013 miles. The difference thus is 8.70029 x 1013 miles
