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Liono4ka [1.6K]

3 years ago

15

In the coordinate plane, point A(-1,-1) is translated to point A' (-3.-3). Under the same translation, the points B(-4,-4) and C

(5.-5) are translated to B' and C' respectively. What are the coordinates of B' and C'?

1 answer:

Nat2105 [25]3 years ago

3 0

Answer:

B' (- 6, - 6 ) , C' (- 7, - 7 )

Step-by-step explanation:

Consider the coordinates of A and A'

A (- 1, - 1 ) , A' (- 3, - 3 )

- 1 to - 3 in both the x and y direction means subtracting 2 units , then

translation rule is

(x, y ) → (x - 2, y - 2 ) , then

B (- 4, - 4 ) → B' (- 4 - 2, - 4 - 2 ) → B' (- 6, - 6 )

C (- 5, - 5 ) → C' (- 5 - 2, - 5 - 2 ) → C' (- 7, - 7 )

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The length of a rectangle is the sum of the width and one. The area direct angle 72 units. What’s the length, in units, of the r

insens350 [35]

Answer:

The length of the rectangle is of 9 units.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

Area of a rectangle:

A rectangle has width $w$ and length $l$ . The area is the multiplication of these measures, that is:

$A = wl$

The length of a rectangle is the sum of the width and one.

This means that $l = w+1$ , or $w = l - 1$

The area direct angle 72 units. What’s the length, in units, of the rectangle

We want to find the length. So

$wl = 72$

$(l-1)l = 72$

$l^2 - l - 72 = 0$

Quadratic equation with $a = 1, b = -1, c = -72$ . So

$\bigtriangleup = (-1)^{2} - 4(1)(-72) = 289$

$l_{1} = \frac{-(-1) + \sqrt{289}}{2*(1)} = 9$

$l_{2} = \frac{-(-1) - \sqrt{289}}{2*(1)} = -8$

Since the length is a positive measure, the length of the rectangle is of 9 units.

8 0

2 years ago

What is the output, or y-value, when you input x = 1 into the function:

Aleksandr [31]

Answer: $y=-6$

Step-by-step explanation:

By definition, a relation is a function if and only if each input value has one and only one output value.

For this exercise it is important to remember that thw "Input values" are the values of the variable "x"and the "Output values" are the values of the variable"y".

In this case you have the following function provided in the exercise:

$y = x^4 - 2x^3 + x^2 + 4x - 10$

Then, to solve this exercise, you need to follow these steps:

Step 1. You have to substitute $x=1$ into the function given.

Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")

You get that this is:

$y = (1)^4 - 2(1)^3 + (1)^2 + 4(1) - 10\\\\y=-6$

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3 years ago

What Is a area with dimensions 1 unit times 1 unit

Ludmilka [50]

Area is length x width so if the dimensions are both 1,
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3 years ago

If f(x) = 62.7"), what is 13)?

Lemur [1.5K]

Answer:

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To find the x

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x−13=0

Add 13

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Replace the variable x

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hope this helps ;)

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3 years ago

Someone helppppp mee please !

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3 years ago