Answer:
Decimal 0.333 to a fraction in simplest form is: 
Step-by-step explanation:
Given the decimal

Multiply and divide by 10 for every number after the decimal point.
There are three digits to the right of the decimal point, therefore multiply and divide by 1000.
Thus,

∵ 0.333×1000 = 333
Let us check if we can reduce the fraction 
For this, we need to find a common factor of 333 and 1000 in order to cancel it out.
But, first, we need to find the Greatest Common Divisor (GCD) of 333, 1000
<u>Greatest Common Divisor (GCD) : </u>
The GCD of a, b is the largest positive number that divides both a and b without a remainder.
Prime Factorization of 333: 3 · 3 · 37
Prime Factorization of 1000: 2 · 2 · 2 · 5 · 5 · 5
As there is no common factor for 333 and 1000, therefore, the GCD is 1.
Important Tip:
- As GCD is 1, therefore the fraction can not be simplified.
Therefore, decimal 0.333 to a fraction in simplest form is: 
Answer:
(7, 0), (-8, 0), (0, 0)
Step-by-step explanation:
y = f(x) = 0
the real solutions are the ones that cross the x-axis because when a point is on the x-axis, its y coordinate will be 0.
=> (7, 0), (-8, 0), (0, 0)
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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The answer is letter C.
In the grocery, the prices per product is represented by:
$2.80/8 ounce
$0.35/ounce
Converted to pounds...
$5.6/lb
In the farmer's market, the prices per product is represented by:<span>
</span>$4.2/ 14 ounces
$0.30/ounce
Converted to pounds...
$4.8/lb
The farmer's market blueberries is cheaper than the grocery's by $0.80 per pound.