3 years ago

How can the rate of a reaction be increased?

Physics

1 answer:

xeze [42]3 years ago

7 0

I think it is D- diluting a solution sorry if i am wrong

You might be interested in

How much power does it take to do 500 J of work in 10 seconds?

Dmitry_Shevchenko [17]

Power = work/time

= 500/10

= 50J/s or 50 watt

7 0

3 years ago

The circuit has a 3 volt EMF and two ohm resistors. How much power in watts does this circuit draw? A) 4.5 , B) 24, C) 1.13 D) 2

dlinn [17]

Answer:

P = 4.5 watts

Explanation:

Given that,

EMF of the circuit, E = 3 volt

The resistance of the resistors, R = 2 ohms

We need to find the power of this circuit. The relation between power, emf and resistance is given by the formula as follows :

$P=\dfrac{V^2}{R}$

Substitute all the values,

$P=\dfrac{3^2}{2}\\\\P=4.5\ W$

So, the power of this circuit is equal to 4.5 watts.

5 0

3 years ago

The force F⃗ pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for

abruzzese [7]

Answer:

The answer is " $\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}$ "

Explanation:

$\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}$

5 0

3 years ago

Margaret, a researcher, desires to conduct a field experiment to determine the effects of a shopping mall's ambience on consumer

vichka [17]

Answer:

Extraneous

Explanation:

Extraneous variables are any variables that you are not intentionally studying in your experiment or test

6 0

3 years ago

Someone please help !!

masha68 [24]

I’m pretty sure it’s c.... hope it helps and hope it’s right.

7 0

3 years ago