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Ilya [14]
3 years ago
7

WHICH IS THE HARDEST SUBSTANCE IN EARTH?

Physics
2 answers:
PIT_PIT [208]3 years ago
8 0
Diamond is the hardest naturally occurring substance found on Earth. 
wlad13 [49]3 years ago
3 0
Diamond is the hardest substance in Earth.
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Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
BabaBlast [244]

Answer:

A. Elements with intermediate numbers of valence electrons are the last chemically stable.

Explanation:

3 0
3 years ago
Read 2 more answers
Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively
Ronch [10]

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

a is the acceleration

For car 1, we have

d_1 = u_1 t + \frac{1}{2}a_1 t^2

where

u_1 = 7 m/s is the initial velocity of car 1

a_1 = 0.4 m/s^2 is the acceleration of car 1

So the equation can be rewritten as

d_1 = 7t + 0.2t^2

For car 2, we have

d_2 = u_2 t + \frac{1}{2}a_2 t^2

where

u_2 = 4 m/s is the initial velocity of car 2

a_2 = 0.5 m/s^2 is the acceleration of car 2

So the equation can be rewritten as

d_2= 5t + 0.25t^2

The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2

And solving for t, we find

2t - 0.05t^2= 0\\t(2-0.05t)=0

Which gives two solutions:

t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
4 years ago
A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At
Pani-rosa [81]

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

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8 0
4 years ago
2. A car is sitting at the top of a hill that is 14 m high. The car has a mass of 53 kg. The car has
Mamont248 [21]
The car has gravitational potential energy (Eg)

Eg = mgh
Eg = (53kg) (9.81N/kg) (14m)
Eg = 7 279.02 J
5 0
3 years ago
Solve it please<br> I need extra details
sasho [114]
RAKE A BREAK AND GO BACK TO IT QUEEN YOULL GET YA ANSWER
5 0
3 years ago
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