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Maru [420]
3 years ago
11

An electron is isolated from an atom and exists in vacuum. A group of scientists collectively state that they can remove part of

the electron’s charge so that it may be transferred to another uncharged particle. Which of the following claims, with appropriate evidence, is correct about the removal of partial charge from the electron? Justify your selection.
Physics
1 answer:
lesya692 [45]3 years ago
5 0

D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values

Explanation:

The electric charge of an object is a property of the object that is related to the ability of the object to experience/exert an electric force: if the object is electrically charge, then it is attracted or repelled by other electrically charged object.

The electric charge of an object depends on the amount of charged particles it has on it. In particular, the fundamental particles that carry electric charge are:

  • Protons: they carry electric charge of +e
  • Electrons: they carry electric charge of -e

Where "e" is the fundamental charge (e=1.6\cdot 10^{-19}C). Therefore, one proton carry a charge of +e and one electron carry a charge of -e.

An electron is a fundamental particle: this means that it cannot be divided into smaller particles. This also means that it is not possible to remove part of the charge of the electron: in fact, it is said that electric charge exists only as discrete values, being a multiple of e. Therefore, the correct statement is

D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values

Learn more about particles:

brainly.com/question/2757829

#LearnwithBrainly

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An attacker at the base of a castle wall 3.95 m high throws a rock straight up with speed 5.00 m/s from a height of 1.60 m above
s344n2d4d5 [400]

Answer:

a) No

b) the rock must have a minimum initial speed of 6.79m/s for it to reach the top of the building.

Explanation:

Given:

Height of the wall = 3.95m

Initial height = 1.60m

Initial speed = 5.00m/s

distance between the initial height and wall top = 3.95 - 1.60 = 2.35m

Using the formula;

v^2 = u^2 + 2as ....1

Where v = final velocity, u = initial velocity, a = acceleration, s = distance travelled

From equation 1

s = (v^2 - u^2)/2a ...2

Since the rock t moving up,

the acceleration = -g = -9.8m/s2

s = maximum height travelled

v = 0 (at maximum height velocity is zero)

Substituting into equation 2

s = (0 - 5^2)/(2×-9.8) = 1.28m

Therefore, the maximum height is 1.28 from his initial height Which is less than the 2.35m of the wall from his initial height. So the rock will not reach the top of the wall

b) Using equation 1:

u^2 = v^2 - 2as

v = 0

a = -9.8m/s

s = 2.35m. (distance between the initial height and wall top)

u^2 = 0 - 2(-9.8 × 2.35)

u^2 = 46.06

u = √46.06

u = 6.79m/s

Therefore, the rock must have a minimum initial speed of 6.79m/s

8 0
4 years ago
What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
emmainna [20.7K]

Answer:

14,300 lines per cm

Explanation:

Given that

The wavelength of visible light ranges from 400 nm to 400nm

It is possible to find the maximum number of lines per cm. This maximum number of lines per cm is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ), where

m = order of diffraction.

λ = wavelength of the incident light.

d = distance between the centers of the two slits.

θ = angle of diffraction of the mth order.

In order to find the least separation that allows the observation of one complete order of spectrum of the visible region, we make use the maximum or highest wavelength of the visible region that we are given, which is 700 nm.

d = mλ / sin (θ)

Again, we need the distance d to be the smallest, so sin (θ) must be the greatest, and for sin (θ) to be the greatest, it has to be equal to 1. Using the longest wavelength is the best idea because when the smallest wavelength is used the longest wavelength would not be diffracted.

d = mλ / sin (θ)

d = 1 * 700nm / 1

d = 700 nm

Next, we say that

n = 1/d

n = 1 / 700 x

n = 1, 430,000 lines per m, converting to cm, we have n = 14,300 lines per cm

3 0
3 years ago
Convert: 8 mm: ____________ cm
vfiekz [6]

-1^10

centi=10 mm and mm=1/10=10^-1 cm

7 0
3 years ago
How much time does it take to use 300 W of power to do 1800 J of work? Round your answer to the nearest whole number. The time i
patriot [66]
Energy = power × time
1800 = 300 × time
time = 1800 ÷ 300 = 6 s

Hope it helped!
4 0
3 years ago
Read 2 more answers
Which location, 23 degrees or 48 degrees would experience the same earthquake at stronger intensity?Explain why.​
BaLLatris [955]

Answer:

48 degress

Explanation:

An earthquake causes many different intensities of shaking in the area of the epicenter where it occurs. So the intensity of an earthquake will vary depending on where you are. Sometimes earthquakes are referred to by the maximum intensity they produce. In the United States, we use the Modified Mercalli Scale. Earthquake intensity is a ranking based on the observed effects of an earthquake in each particular place. Therefore, each earthquake produces a range of intensity values, ranging from highest in the epicenter area to zero at a distance from the epicenter.

6 0
3 years ago
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