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Maru [420]
2 years ago
11

An electron is isolated from an atom and exists in vacuum. A group of scientists collectively state that they can remove part of

the electron’s charge so that it may be transferred to another uncharged particle. Which of the following claims, with appropriate evidence, is correct about the removal of partial charge from the electron? Justify your selection.
Physics
1 answer:
lesya692 [45]2 years ago
5 0

D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values

Explanation:

The electric charge of an object is a property of the object that is related to the ability of the object to experience/exert an electric force: if the object is electrically charge, then it is attracted or repelled by other electrically charged object.

The electric charge of an object depends on the amount of charged particles it has on it. In particular, the fundamental particles that carry electric charge are:

  • Protons: they carry electric charge of +e
  • Electrons: they carry electric charge of -e

Where "e" is the fundamental charge (e=1.6\cdot 10^{-19}C). Therefore, one proton carry a charge of +e and one electron carry a charge of -e.

An electron is a fundamental particle: this means that it cannot be divided into smaller particles. This also means that it is not possible to remove part of the charge of the electron: in fact, it is said that electric charge exists only as discrete values, being a multiple of e. Therefore, the correct statement is

D) Partial charge cannot be removed, because charge is a discrete quantity that may exist only at certain values

Learn more about particles:

brainly.com/question/2757829

#LearnwithBrainly

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Answer:

83.6°

Explanation:

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So, substituting these values into the equation,

n₁sinθ₁ = n₂sinθ₂

1.5 × sinθ₁ = 1 × sin90

1.5 × sinθ₁  = 1

sinθ₁ = 1/1.5

sinθ₁ = 0.6667

θ₁  = sin*(0.6667)

θ₁  = 41.8°

So, for total internal reflection, an incidence angle of 41.8° is required. So, a full convergence angle of 2 × 41.8° = 83.6° is required for the whole bundle of rays.

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Answer:

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Now, we can clear the mass from the equation above:

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