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OleMash [197]
3 years ago
11

I’m not sure which answer it is !??

Mathematics
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

Its A or B if not then sorry

Step-by-step explanation:

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I need help with this
avanturin [10]

Answer:

1/16

Step-by-step explanation:

-1/4*-1/4

= -*- = +

= 1/4*1/4

=1/16

4 0
3 years ago
Read 2 more answers
PLEASE PLEASE ANSWER FAST. there are 2 types of probability. one is called theoretical and the other has two names, they are wha
jonny [76]

Answer:

Actual probability or experimental probability is the name of the "other" type of probability. We can always calculate in theory how an event will go: if you flip a coin twice, you should get one head and one tail. Yet in actuality, if you run an experiment you won't always get that theoretical result.

8 0
3 years ago
What is the solution to −1.2b−5.3≥1.9
wel

Answer:

If you want me to solve for b then

b  ≤  − 6





3 0
3 years ago
Read 2 more answers
Find the probability that when a hand of 7 cards are drawn from the well-shuffled deck of 52 cards, it contains
wlad13 [49]

Answer:

(i) 0/7

(ii) 3/7

Step-by-step explanation:

In a deck of 52 playing cards, there are 13 cards of each clubs, spades, diamonds, and hearts. From those 13 cards, each group has 1 King, Queen, Jack respectively.

No.of total outcomes = 7

(i) In the entire 52 cards, there will be 4 Kings.

The probability of getting 4 kings in 7 cards can be 4/7.

But since there are only 4 kings (4<7), the probability of getting all kings in 7 cards would be 0/7.

6 0
3 years ago
You own 24 CDs. You want to randomly arrange 7 of them in a CD rack. What is the probability that the rack ends up in alphabetic
goblinko [34]

Answer:

the probability that the rack ends up in alphabetical order is 0.0001984

Step-by-step explanation:

Given that:

You own 24 CDs. You want to randomly arrange 7 of them in a CD rack.

Th probability that the rack ends up in alphabetical order can be determined by taking note of the permutations and combinations.

From above; all possible permutations of size 7 we can derive from 24 is

24P7

Similarly,we are meant  to estimate  all the possible ways a unique set of 7 things can be gotten from a total of 24

i.e

24 C7

∴

The probability = \dfrac{^{24}{C}_7}{^{24}{P}_7}

= \dfrac{\dfrac{24!}{7!(24-7)!}  }{ \dfrac{24!}{(24-7)!} }

=\dfrac{\dfrac{24!}{7!(17)!}  }{ \dfrac{24!}{(17)!} }

= \dfrac{346104}{ 1.74436416 \times 10^9}

= 0.0001984

the probability that the rack ends up in alphabetical order is 0.0001984

3 0
3 years ago
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