None of the offered choices is correct.
The radical cannot be simplified. If rewritten, it must be written as something like
![x \sqrt[3]{ \frac{6}{x}}](https://tex.z-dn.net/?f=%20x%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B6%7D%7Bx%7D%7D%20)
or
90 counterclockwise hope I’m right
I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
Answer:
The charge for admission is $6 and the charge for each ride is $2
Step-by-step explanation:
Let
x ----> the charge for admission
y ----> the charge for each ride
we have that
-----> equation A
-----> equation B
Solve the system by elimination
Subtract equation B from equation A

Find the value of x
substitute the value of y in any equation




therefore
The charge for admission is $6 and the charge for each ride is $2
3y + 12 = 6x
3y = 6x - 12
y = 2x - 4
2y = 4x + (-8)
y = 2x + (-4)....the same as y = 2x - 4
b would have to be a -8