The longest possible integer length of the third side of the triangle is 6 < x < 28
The sum of any two sides must be greater than the third side for a triangle to exist
let the third side be x
x + 11 > 17 and x + 17 > 11 and 11 + 17 > x
x > 6 and x > - 6 and x < 28
The longest possible integer length of the third side of the triangle is 6 < x < 28
The length of the 3 sides of a triangle needs to always be among (however no longer the same) the sum and the difference of the opposite two sides. As an example, take the instance of two, 6, and seven. and. consequently, the third side period should be extra than 4 and less than 8.
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12/2 , because 12 divided by 2 is 6
Answer:44
Step-by-step explanation:
-8(-6) -4
48 -4
44
The answer is 5. You get 5 by added the 6 and 4 together to get 10 and the 2 is lowest you can go so you keep that the same.
590.4
I believe let me know if it wrong
