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Lelu [443]
3 years ago
6

You are scheduled to receive $10,000 in one year. what will be the effect of an increase in the interest rate on the present val

ue of this cash flow?
a.it will cause the present value to fall.
b.it will cause the present value to rise.
c.it will have no effect on the present value.
d.the effect cannot be determined with the information provided
Business
1 answer:
kiruha [24]3 years ago
5 0
I think it is d but i am not sure i aint that good at this stuff 
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An increase in u. S. Interest rates relative to german interest rates would likely ____ the u. S. Demand for euros and ____ the
Naya [18.7K]

An increase in US. Interest rates relative to German interest rates would likely reduce the u. S. Demand for euros and increase the supply of euros for sale.

<h3>What is the impact of an increase in interest rate on a country's currency?</h3>

When the interest rate of a country's currency increases, the value of that currency increases. As a result, there would be an increase in the demand for that currency relative to other currencies.

When the US interest rates increase relative to that of Germany, the value of the dollar would increase. This would lead to an increase in the demand for the dollar and a decrease in demand for the euros.

To learn more about currencies, please check: brainly.com/question/17180334

6 0
2 years ago
"You plan to buy a piece of machinery worth $50,000 then you plan to sell it at the end of its 15-year life cycle for $5,000. Wh
Aleks04 [339]

Answer:

$3,000 and $35,000

Explanation:

The computations are shown below:

The depreciation expense would be

=(Original cost - residual value) ÷ (useful life)

= ($50,000 - $5,000) ÷ (15 years)

= ($45,000) ÷ (15 years)  

= $3,000

In this method, the depreciation is same for all the remaining useful life

The book value would be

= (Original cost of equipment) - (depreciation × number of years)

= ($50,000) - ($3,000 × 5 years)

= $50,000 - $15,000

= $35,000

8 0
3 years ago
Where can you find an image database of free and simple graphics in many
Ede4ka [16]

Answer:C

Explanation:

just did it on apex

5 0
3 years ago
Suppose that output (Y ) in an economy is given by the following aggregate production function: Yt = Kt + Nt where Kt is capital
shusha [124]

Answer:

Check the explanation

Explanation:

Yt = Kt + Nt

Taking output per worker, we divide by Nt

Yt/Nt = Kt/Nt + 1

yt = kt + 1

where yt is output per worker and kt is capital per worker.

a) With population being constant, savings rate s and depreciation rate δ.

ΔKt = It - δKt

dividing by Nt, we get

ΔKt/Nt = It/Nt - δKt/Nt ..... [1]

for kt = Kt/Nt, taking derivative

d(kt)/dt = d(Kt/Nt)/dt ... since Nt is a constant, we have

d(kt)/dt = d(Kt/Nt)/dt = (dKt/dt)/Nt = ΔKt/Nt = It/Nt - δKt/Nt = it - δkt

thus, Capital accumulation Δkt = i – δkt

In steady state, Δkt = 0

That is I – δkt = 0

S = I means that I = s.yt

Thus, s.yt – δkt = 0

Then kt* = s/δ(yt) = s(kt+1)/(δ )

kt*= skt/(δ) + s/(δ)

kt* - skt*/(δ) = s/(δ)

kt*(1- s/(δ) = s/(δ)

kt*((δ - s)/(δ) = s/(δ)

kt*(δ-s)) = s

kt* = s/(δ -s)

capital per worker is given by kt*

b) with population growth rate of n,

d(kt)/dt = d(Kt/Nt)/dt =

= \frac{\frac{dKt}{dt}Nt - \frac{dNt}{dt}Kt}{N^{2}t}

= \frac{dKt/dt}{Nt} - \frac{dNt/dt}{Nt}.\frac{Kt}{Nt}

= ΔKt/Nt - n.kt

because (dNt/dt)/Nt = growth rate of population = n and Kt/Nt = kt (capital per worker)

so, d(kt)/dt = ΔKt/Nt - n.kt

Δkt = ΔKt/Nt - n.kt = It/Nt - δKt/Nt - n.kt ......(from [1])

Δkt = it - δkt - n.kt

at steady state Δkt = it - δkt - n.kt = 0

s.yt - (δ + n)kt = 0........... since it = s.yt

kt* = s.yt/(δ + n) =s(kt+1)/(δ + n)

kt*= skt/(δ + n) + s/(δ + n)

kt* - skt*/(δ + n) = s/(δ + n)

kt*(1- s/(δ + n)) = s/(δ + n)

kt*((δ + n - s)/(δ + n)) = s/(δ + n)

kt*(δ + n -s)) = s

kt* = s/(δ + n -s)

.... is the steady state level of capital per worker with population growth rate of n.

3. a) capital per worker. in steady state Δkt = 0 therefore, growth rate of kt is zero

b) output per worker, yt = kt + 1

g(yt) = g(kt) = 0

since capital per worker is not growing, output per worker also does not grow.

c)capital.

kt* = s/(δ + n -s)

Kt*/Nt = s/(δ + n -s)

Kt* = sNt/(δ + n -s)

taking derivative with respect to t.

d(Kt*)/dt = s/(δ + n -s). dNt/dt

(dNt/dt)/N =n (population growth rate)

so dNt/dt = n.Nt

d(Kt*)/dt = s/(δ + n -s).n.Nt

dividing by Kt*

(d(Kt*)/dt)/Kt* = s/(δ + n -s).n.Nt/Kt* = sn/(δ + n -s). (Nt/Kt)

\frac{sn}{\delta +n-s}.\frac{Nt}{Kt}

using K/N = k

\frac{s}{\delta +n-s}.\frac{n}{kt}

plugging the value of kt*

\frac{sn}{\delta +n-s}.\frac{(\delta + n -s)}{s}

n

thus, Capital K grows at rate n

d) Yt = Kt + Nt

dYt/dt = dKt/dt + dNt/dt = s/(δ + n -s).n.Nt + n.Nt

using d(Kt*)/dt = s/(δ + n -s).n.Nt from previous part and that (dNt/dt)/N =n

dYt/dt = n.Nt(s/(δ + n -s) + 1) = n.Nt(s+ δ + n -s)/(δ + n -s) = n.Nt((δ + n)/(δ + n -s)

dYt/dt = n.Nt((δ + n)/(δ + n -s)

dividing by Yt

g(Yt) = n.(δ + n)/(δ + n -s).Nt/Yt

since Yt/Nt = yt

g(Yt) = n.(δ + n)/(δ + n -s) (1/yt)

at kt* = s/(δ + n -s), yt* = kt* + 1

so yt* = s/(δ + n -s) + 1 = (s + δ + n -s)/(δ + n -s) = (δ + n)/(δ + n -s)

thus, g(Yt) = n.(δ + n)/(δ + n -s) (1/yt) =  n.(δ + n)/(δ + n -s) ((δ + n -s)/(δ + n)) = n

therefore, in steady state Yt grows at rate n.

5 0
3 years ago
McDonald’s pressed on with the strategic plan of offering all-day breakfast in spite of initial struggles because strategic deci
Elenna [48]

Answer: True

Explanation:

Strategic decisions do indeed take long-term commitment because they are meant to help the company in the long term not the short.

Strategic decisions usually set goals and achieve results in the long term. They are not expected to yield results in the short terms which is why MacDonald's pressed on with the all-day breakfast despite initial challenges.

7 0
2 years ago
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