So, we are given 5^8. It was happy and content. But then... we had to write it as a quotient of two exponential terms with the same base in four different ways and use negative or zero exponents and ahhhhhh!!!

... anyways...

We'll build a quotient of two exponential terms with the same base 5. Something like this:

5^a / 5^b

We need them to make 5^8 when we are done. I'll first use a zero exponent.

[1] Now, zero exponents are nice since they make things equal 1. Like 5^0 = 1. Well, obviously, 5^8 / 1 = 5^8. So, our first quotient can be:

5^8 / 5^0

Done.

[2] Let's try this on its head. This one's a little weird. Remember that negative exponents flip things upside down. So 5^-8 = 1/5^8 and 1/5^-8 = 5^8 for example. In fact... that's the answer!

5^0 / 5^-8 = 5^8

Done.

[3] Let's try to not use 0s or 8s. We can be clever and do something like this:

5^-1 / 5^-9

What the heck is that? Well, we just flip them and get:

5^-1 / 5^-9 = 5^9 / 5^1 = 5^8

Done.

[4] Can you come up with one last trick on your own? Try it!

3 0

3 years ago

Will give brainliest!

Gala2k [10]

Check the picture below, it hits the ground when y = 0.

$\bf ~~~~~~\textit{initial velocity}\\\\
\begin{array}{llll}
~~~~~~\textit{in feet}\\\\
h(t) = -16t^2+v_ot+h_o \\\\
\end{array} 
\quad 
\begin{cases}
v_o=\stackrel{0}{\textit{initial velocity of the object}}\\\\
h_o=\stackrel{162}{\textit{initial height of the object}}\\\\
h=\stackrel{}{\textit{height of the object at "t" seconds}}
\end{cases}
\\\\\\
h(t)=-16t^2+0t+162\implies 0=-16t^2+162\implies 16t^2=162
\\\\\\
t=\cfrac{162}{16}\implies t=\cfrac{81}{8}\implies t=10\frac{1}{8}$

6 0

3 years ago

On October 15, 2019, Jon purchased and placed in service a used car. The purchase price was $38,000. This was the only business

san4es73 [151]

Answer:

cost recovery deduction = $1520

Step-by-step explanation:

given data

purchase price = $38,000

used the car business = 80%

used the car personal = 20%

solution

cost recovery limit are

cost recovery limit = asset value × statutory % × mid quater convention ..........1

we know car which have 5 year MACRS convention and as per MACRS depreciated 20 % in 1st year

and here this car is use so no 1st year depreciation

so we use MACRS statutory % method

cost recovery limit = $38000 × 5%

cost recovery limit = $1900

we know maximum limit is $3160

so cost of recovery is $1900

cost recovery deduction is

cost recovery deduction = cost recovery limit - personal use

cost recovery deduction = $1900 - ( $1900 × 20% )

cost recovery deduction = $1520

6 0

3 years ago