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Mamont248 [21]
3 years ago
9

Find the value that completes the square r^2-30r+__

Mathematics
1 answer:
babunello [35]3 years ago
6 0
r^2-30r+225=(r-15)^2
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When the polynomial is written in standard form, what are the values of the leading coefficient and the constant?
Semenov [28]

Answer:

leading coefficient -3

constant 2

Step-by-step explanation:

Standard from is from largest power to smallest power

-3x^2 +5x +2

The leading coefficient is the number in front of the largest power of x

-3

The constant is the number without a power of x ( or x^0)

2

4 0
3 years ago
What is the product of (2p + 7)(3p2 + 4p – 3)?
Nady [450]

Answer:

(2p+7)(3p²+4p-3)

2p(3p²+4p-3)+7(3p²+4p+3)

(6p³+8p²-6p)+ (21p²+28p+21)

6p³+29p²-6p+21

3 0
2 years ago
A 26' Long painting is how many yards Long
Alenkinab [10]
In one foot, there are 0.33 yards.
Therefore, you need to multiply 26 by 0.33
20x0.33= 6.6
6x0.33= 1.98 yards.
6.6+1.98= 8.58
Therefore, in a 26' long painting, there are 8.58 yards
Hope this helps :) 
3 0
3 years ago
Read 2 more answers
Find the y-intercept of the line on the graph.​
horrorfan [7]
The y intercept is 2,0
4 0
3 years ago
Electrical wire is being wound around a drum with a radius of 1.1 meters. How much line (to the nearest hundredth of a meter) wo
Rudik [331]

Answer:

6.81m

Step-by-step explanation:

Using the formula for finding the length of am arc

L = theta/360° × 2πr

theta is the angle subtended by the drum in rotation

r is the radius of the drum

Given theta = 315.7°

r = 1.1m

Substituting the given values into the formula we have:

L = 315.7/360 × 2π(1.1)

L = 315.7/360 × 2.2π

L = 315.7/360 × 2.2(3.14)

L = 315.7/360 × 6.91

L = 6.81metres

Line of about 6.81metres will be wounded around the drum

7 0
3 years ago
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