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navik [9.2K]
3 years ago
8

Suppose you wish to test if a number cube (die) is loaded or not. if the die is not loaded, the theoretical probabilities for ea

ch roll should be:
Mathematics
1 answer:
iris [78.8K]3 years ago
6 0
I believe the answer you're looking for is 1/6which would be 16.6%
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y=63

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Which of the numbers below is greater than -4.5? Select all that apply.
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A, C, and D

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You run one lap around a mile track every8 minutes. Your friend runs around the same track every 10 minutes. You both start at t
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You are constructing a cardboard box with the dimensions 2 m by 4 m. You then cut equal-size squares ( x by x squares) from each
romanna [79]

Answer:

<em>x</em> = 0.423 m

Step-by-step explanation:

Volume of the box = length × width × height

The height is given by the length of a side of the square.

height = <em>x</em>

The width and height are gotten by subtracting twice the side of the square form each dimension of the cardboard (since two squares are cut along each dimension).

length = 4 - 2<em>x</em>

width = 2 - 2<em>x</em>

<em />

Volume, V = x(4-2x)(2-2x) = 8x - 12x^2 + 4x^3

To find the maximum, we differentiate <em>V</em> with respect to <em>x</em> and equate the derivative to 0.

\dfrac{dV}{dx} = 8-24x+12x^2 = 0

Simplify by dividing by 4.

2-6x+3x^2 = 0

Using the quadratic formula,

<em>x</em> = 0.423 m or <em>x</em> = 1.577 m

To determine which values gives maximum, we differentiate the first derivative which gives

\dfrac{d^2V}{dx^2} = -6+6x

The maximum value occurs when \dfrac{d^2V}{dx^2} is negative.

At <em>x</em> = 1.577,

\dfrac{d^2V}{dx^2} = -6+6(1.577) = 3.462

This is positive, so it is minimum.

At <em>x</em> = 0.423,

\dfrac{d^2V}{dx^2} = -6+6(0.423) = -3.462

This gives a negative value. Therefore, it is a maximum.

Hence, the maximum volume is obtained when <em>x</em> = 0.423 m.

6 0
3 years ago
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