Answer: Friction is like when u take two stick's and rub it together to make fire when you use friction it can produce heat. Applied force is like and applied to an object or person if a person is pushing a desk across the room then there is applied force.
Kinetic energy of the ball is (mv²) / 2, where m is the mass and v is the velocity
So plugging in the mass and the velocity into the kinetic energy expression, you get:
Kinetic energy of the ball = (mv²) / 2
(0.3125/32) times (132)² divided by 2 = 85 ft-lbs
Kinetic energy of the ball = 85 ft-lbs
Answer:
w2=5.1736x10^-6m
Explanation:
The relation between the wavelength and width is:
sin(Ф)=m*λ/w
Since the mass and the angle is the same in both cases so:
sin(Ф)=m*λ1/w1
sin(Ф)=m*λ2/w2
The mass and the sinФ are factor in both elements so:
λ2/w2=λ1/w1
w2=w1*λ2/λ1
w2=4.1x10^-6m*665x10^-9m/527x10^-9m
w2=5.1736x10^-6m
Answer:
This is an example of Inelastic colission
Explanation:
Step one:
given:
mass of moose m1 = 620 kg
mass of train m2= 10,000kg
Initial velocity of moose u1= 0 m/s
Initial velocity of train v1 = 10m/s
combined velocity of the system is given as v
Applying the conservation of momentum equation we have
m1u1+ m2u1= (m1+m2)V
substitutting we have
620*0+10000*10= (620+10000)V
100000= 10620V
divide both sides by 10620
V = 100000/10620
V=9.41m/s
The velocity of the moose after impact is 9.41m/s