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Rama09 [41]
3 years ago
12

If you are driving an oscillatory system at a certain frequency, but the amplitude is much smaller than it could be, you can be

certain that
1. The driving frequency is too low.
2. The driving frequency is too high.
3. The driving frequency is not matched to the natural frequency of the oscillatory system.
Physics
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

3. The driving frequency is not matched to the natural frequency of the oscillatory system.

Explanation:

  • It is the condition of resonance when the one body that oscillates with a maximum amplitude when the frequency of the applied force is equal to the natural frequency of the body.
  • Every body has its own natural frequency.
  • Here the driving force may be more or less but we are sure that it is not equal to the natural frequency of oscillatory system. Hence the force is not in resonance with the oscillatory system.

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Which type of map would you most likely use to locate mineral deposits? A. topographic B. geologic C. satellite D. hazard
qwelly [4]
I think you would be using a topographic Map, So the answer should be A
3 0
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Nhận xét về nét riêng trong cách thể hiện tình yêu của xuân quỳnh qua 3 khổ thTrong thí nghiệm về giao thoa sóng trên mặt nước g
WINSTONCH [101]

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3 years ago
In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6
stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

                                      r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

                                      r₂= 7.5 cm

head upto water level is to rise = 60 + 5

                                          = 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q  

 π r₁² v₁ = π r₂² v₂  = 0.015

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{7.5^2}{5^2} v_2

 v_1= 2.25 v_2

 v_2 = \dfrac{0.015}{\pi r_2^2}

 v_2 = \dfrac{0.015}{\pi 0.075^2}

    v₂ = 0.848 m/s

    v₁ = 1.908 m/s

Applying Bernoulli's equation

 P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h

 P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65

 P_p= 635539.32 Pa

 P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0
4 years ago
Metal surfaces on spacecraft in bright sunlight develop a net electric charge.
koban [17]

Answer:

Positive.

Explanation:

As a consequence of the photoelectric effect, electrons that will get hit by sufficiently energetic photons will abandon the metal surfaces exposed to bright sunlight. This decreases the negative charge of the surface, thus causing it to develop a positive net charge.

5 0
3 years ago
A uniform wooden plank with a mass of 75kg and length of 5m is placed on top of a brick wall so that 1.5m of plank extends beyon
jek_recluse [69]

Answer:

x₂ = 1.33 m

Explanation:

For this exercise we must use the rotational equilibrium condition, where the counterclockwise rotations are positive and the zero of the reference system is placed at the turning point on the wall

            Στ = 0

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where W₁ is the weight of the woman, W₂ the weight of the table.

Let's find the distances.

Since the table is homogeneous, its center of mass coincides with its geometric center, measured at zero.

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The distance of the person is x₂ measured from the turning point, at the point where the board begins to turn the girl must be on the left side so her torque must be negative

            x₂ = \frac{M_1g  }{m_2 g} \ x_1

           

let's calculate

           x₂ = \frac{100}{75}  \ 1

           x₂ = 1.33 m

7 0
3 years ago
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