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stepladder [879]
3 years ago
12

If a single strand of DNA were stretched out, how far would it reach?

Physics
2 answers:
xz_007 [3.2K]3 years ago
6 0
If unwound and tied together the strands of DNA in 1 cell would reach almost 6 feet but would only be 50 trillionths of an inch wide.
kipiarov [429]3 years ago
3 0

Answer: 2-3 meters long

Explanation:

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Using the law of conservation of angular momentum, estimate how fast a collapsed stellar core would spin if its initial spin rat
Nataly_w [17]

Answer:

\omega_{f} = 1000000\,\frac{rev}{day}

Explanation:

The law of conservation of angular momentum states that angular momentum remains constant when there is no external moment or forces applied to the system. Let assume that star can be modelled as an sphere, then:

\frac{2}{5}\cdot M\cdot R_{o}^{2} \cdot \omega_{o} = \frac{2}{5}\cdot M\cdot R_{f}^{2} \cdot \omega_{f}

The final angular speed is:

\omega_{f} = \omega_{o}\cdot (\frac{R_{o}}{R_{f}})^{2}

\omega_{f} = (1\,\frac{rev}{day} )\cdot (\frac{10000\,km}{10\,km} )^{2}

\omega_{f} = 1000000\,\frac{rev}{day}

3 0
2 years ago
What type of specialized training is necessary to learn the skills needed to work in this career field
Nonamiya [84]

Answer:

DONTKNOW NEED CAREER FILD FIRST TO ANWSER

Explanation:

5 0
3 years ago
Tamsen is interested in history, and read that because of its regular period, the pendulum constituted the basis of the most acc
geniusboy [140]

We will apply the concept of period in a pendulum, defined as the product between 2\pi by the square root of the length over gravity, this is mathematically

T = 2\pi \sqrt{\frac{L}{g}}

Here,

T = Period

L = Length

g = Acceleration due to gravity

For the period to be 1 second, then we must look for the necessary length for such a requirement so

1 = 2\pi \sqrt{\frac{L}{9.8}}

(\frac{1}{2\pi})^2 = \frac{L}{9.8}

L = 9.8(\frac{1}{2\pi})^2

L = 0.2482m

The meter's length would be slight less than one-fourth of its current length. Also, the number of significant digits depends only on how precisely we know g, because the time has been defined to be exactly 1s.

Therefore the correct answer is C.

3 0
3 years ago
When the Apollo 11 lunar module Eagle lands on the moon it comes to a stop 10m above the surface of the moon. The last 10m it fr
Scrat [10]

Answer:

i) 3.514 s, ii) 5.692 m/s

Explanation:

i) We can use Newton's second law of motion to find out how long does it take for the Eagle to touch down.

as the equation says for free-falling

h = ut +0.5gt^2

Here, h = 10 m, g = acceleration due to gravity = 1.62 m/s^2( on moon surface)

initial velocity u = 0

10 = 0.5×1.62t^2

t = 3.514 seconds

Therefore, it takes t = 3.514 seconds for the Eagle to touch down.

ii) use Newton's 1st equation of motion to calculate the velocity of the lunar module when it hits the surface of the moon

v = u + gt

v = 0+ 1.62×3.514

v= 5.692 m/s

7 0
3 years ago
The first law of thermodynamics states that energy transforms matter in different ways by creating and destroying it.
tensa zangetsu [6.8K]
The first law of thermodynamics states that energy cannot be created nor destroyed. It can be transformed from one form of energy to another, but the energy in an isolated system remains constant.

The answer then would be letter B. False. 
5 0
3 years ago
Read 2 more answers
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