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DanielleElmas [232]
3 years ago
11

A basketball player is running at 5.00 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains

his horizontal velocity. What vertical velocity does he need to rise 0.750 m above the floor?
Physics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

3.834 m/s

Explanation:

h = 0.750 m

vx = 5 m/s

Let the initial vertical velocity is vy.

Final vertical velocity is zero

use third equation of motion along y axis

v^2 = vy^2 - 2 x g x h

0 = vy^2 - 2 x 9.8 x 0.75

vy^2 = 14.7

vy = 3.834 m/s

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Fiesta28 [93]
I think the correct answer choice is c
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2). If you record a wave going 4m/s and the Period of the wave was<br> 60s, how long was the wave?
Taya2010 [7]

Answer:240 meters

Explanation:60×4

8 0
3 years ago
Problema 1. Un Clavadista se lanza desde un trampolín a diferentes alturas 10 m, 3 m, y 1 m, Calcular:
Salsk061 [2.6K]

La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.

<h3 /><h3>Velocidad </h3>

La velocidad es la relación entre la distancia total recorrida y el tiempo total empleado. Está dado por:

Velocidad = distancia/tiempo

Para 10m de altura:

  • Velocidad = 10 m/1.42 s = 7.04 m/s

Para 3m de altura:

  • Velocidad = 3 m/0.78 s = 3.84 m/s

Para 1m de altura:

  • Velocidad = 1 m/0.44 s = 2.27 m/s

La velocidad del buzo es de 7.04 m/s, 8.84 m/s y 2.27 m/s respectivamente.

Obtenga más información sobre la velocidad en: brainly.com/question/4931057

4 0
2 years ago
An 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its
nikdorinn [45]

Answer:

The average induced emf in the loop is 0.20 V

Explanation:

Given:

Radius of loop r = \frac{d}{2} = 9.25 \times 10^{-2} m

Magnetic field B = 1.5 T

Change in time \Delta t = 0.20 sec

According to the faraday's law,

Induced emf is given by

    \epsilon = -\frac{\Delta \phi}{\Delta t}

Where \phi = magnetic flux

  \phi = BA\cos0                                ( here \theta = 0 )      

Where A = \pi r^{2}

We neglect minus sign because it's shows lenz law

   \epsilon  = \frac{B \pi r^{2}  }{\Delta t}

   \epsilon = \frac{1.5 \times 3.14 \times (9.25 \times 10^{-2} )^{2} }{0.20}

   \epsilon = 0.20 V

Therefore, the average induced emf in the loop is 0.20 V

4 0
3 years ago
Practice questions, will mark brainliest!
andrew-mc [135]

Answer:

266.67Watts

Explanation:

Time = 2.5hr to seconds

3600s = 1hr

2.5hrs = 3600×2.5= 9000s

Force = 32N

Distance = 75km  to m

1000m = 1km

75km = 1000×75 = 75000m

Power = workdone / time

Work = force × distance

Therefore work = 32N × 75000m

Work = 2400000Nm

Power = work ➗ time

Power = 2400000Nm ➗ 9000s

Power = 266.67Watts

Watts is the S. i unit of power

I hope this was helpful, please mark as brainliest

4 0
2 years ago
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