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DanielleElmas [232]
4 years ago
11

A basketball player is running at 5.00 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains

his horizontal velocity. What vertical velocity does he need to rise 0.750 m above the floor?
Physics
1 answer:
makkiz [27]4 years ago
5 0

Answer:

3.834 m/s

Explanation:

h = 0.750 m

vx = 5 m/s

Let the initial vertical velocity is vy.

Final vertical velocity is zero

use third equation of motion along y axis

v^2 = vy^2 - 2 x g x h

0 = vy^2 - 2 x 9.8 x 0.75

vy^2 = 14.7

vy = 3.834 m/s

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The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.
mrs_skeptik [129]

Explanation:

The orbital radius of the Earth is r_1=1.496\times 10^{11}\ m

The orbital radius of the Mercury is r_2=5.79 \times 10^{10}\ m

The orbital radius of the Pluto is r_3=5.91 \times 10^{12}\ m

We need to find the time required for light to travel from the Sun to each of the  three planets.

(a) For Sun -Earth,

Kepler's third law :

T_1^2=\dfrac{4\pi ^2}{GM}r_1^3

M is mass of sun, M=1.989\times 10^{30}\ kg

So,

T_1^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 1.496\times 10^{11}\\\\T_1=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times1.496\times10^{11}}\\\\T_1=2\times 10^{-4}\ s

(b) For Sun -Mercury,

T_2^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.79 \times 10^{10}\ m\\\\T_2=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.79 \times 10^{10}}\ m\\\\T_2=1.31\times 10^{-4}\ s

(c) For Sun-Pluto,

T_3^2=\dfrac{4\pi ^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times 5.91 \times 10^{12}\\\\T_3=\sqrt{\dfrac{4\pi^{2}}{6.67\times10^{-11}\times1.989\times10^{30}}\times 5.91 \times 10^{12}}\\\\T_3=1.32\times 10^{-3}\ s

8 0
3 years ago
please help with questions
kaheart [24]

Answer:

Please selection one of the following

3 0
2 years ago
a metal sphere with a mass of 90 kg rolls along at 16m/s and strikes a stationary sphere having a mass of 140kg. the first spher
baherus [9]
13.2 meters per second
7 0
3 years ago
Helpp pls
Kipish [7]

Answer:

The intensity of the electric field is

|E|=10654.37 \:N/C

Explanation:

The electric field equation is given by:

|E|=k\frac{q}{d^{2}}

Where:

  • k is the Coulomb constant
  • q is the charge at 0.4100 m from the balloon
  • d is the distance from the charge to the balloon

As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.

Then, let's use the equation written above.

|E|=(9*10^{9})\frac{1.99*10^{-7}}{0.41^{2}}

|E|=10654.37 \:N/C

I hope it helps you!

5 0
3 years ago
Two identical wind-up cars A and B are released. Car B has a 2 kilogram weight strapped to the back of the car. Which will have
koban [17]

Answer:

Car A would have a better average speed

Explanation:

added weight to a object that is self propelled will be slower than a identical object with no added weight

7 0
3 years ago
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