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DanielleElmas [232]
3 years ago
11

A basketball player is running at 5.00 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains

his horizontal velocity. What vertical velocity does he need to rise 0.750 m above the floor?
Physics
1 answer:
makkiz [27]3 years ago
5 0

Answer:

3.834 m/s

Explanation:

h = 0.750 m

vx = 5 m/s

Let the initial vertical velocity is vy.

Final vertical velocity is zero

use third equation of motion along y axis

v^2 = vy^2 - 2 x g x h

0 = vy^2 - 2 x 9.8 x 0.75

vy^2 = 14.7

vy = 3.834 m/s

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¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula
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Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

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