The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer: C
Step-by-step explanation:
12 x 6 x 4= 288 also do you do time4learning?
Answer:
-6
Step-by-step explanation:
5p - 14 = 8p + 4
Subtract 8p from both sides.
-3p - 14 = 4
Add 14 to both sides.
-3p = 18
Divide both sides by -3.
p = -6
Answer: -6
None of these are correct my calculations are 11 tons 2138 Ibs 28 oz
