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3 years ago

Solve the following equation: x÷6-3=1

Mathematics

2 answers:

Tju [1.3M]3 years ago

5 0

Answer:

x = 24

Step-by-step explanation:

1x / 6 - 3 = 1

+3 +3

1x / 6 = 4

x6 x6

1x = 24

/1 /1

x = 24

zavuch27 [327]3 years ago

4 0

Answer:

x = 24

Step-by-step explanation:

Step 1: Write equation

x/6 - 3 = 1

Step 2: Solve for x

Add 3 to both sides: x/6 = 4

Multiply both sides by 6: x = 24

Step 3: Check

Plug in x to verify if it's a solution.

24/6 - 3 = 1

4 - 3 = 1

1 = 1

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Match each quadratic equation with its solution set.

Marianna [84]

Answer:

( 8 , - 8) => x² - 55 = 9

( 4 , - 4) => 2x² - 32 = 0

(5 , - 5) => 4x² - 100 = 0

(11 , - 11) => x² - 140 = -19

( 3, - 3) => 2x² - 18 = 0

Step-by-step explanation:

$2x^2 - 32 = 0\\\\2(x^2 - 16 ) = 0 \\\\x^2 - 16 = 0 \\\\x^2 = 16 \\\\x = \sqrt {16 } = \pm 4$

x = ( 4 , - 4)

$4x^2 - 100 = 0 \\\\4(x^2 - 25 ) = 0\\\\x^2 - 25 = 0 \\\\x^2 = 25 \\\\x= \sqrt{25} = \pm 5$

x = ( 5 , - 5 )

$x^2 - 55 = 9 \\\\x^2 = 9 +55\\\\x^2 = 64\\\\x = \sqrt{64} = \pm 8$

x= ( 8 , - 8)

$x^2 - 140 = - 19\\\\x^2 = -19 + 140 \\\\x^2 = 121 \\\\x= \sqrt{121} = \pm 11$

x = ( 11 , -11)

$2x^2 - 18 = 0\\\\2(x^2 - 9) = 0\\\\x^2- 9 = 0 \\\\x^2 = 9 \\\\x = \sqrt9 = \pm 3$

x = ( 3 , - 3)

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What is the missing numerator? blank over five plus eighteen over twenty equals thirty over twenty 8 5 3 2

Oliga [24]

Given:

$\dfrac{?}{5}+\dfrac{18}{20}=\dfrac{30}{20}$

To find:

The missing value.

Solution:

Let x be the missing value.

We have,

$\dfrac{x}{5}+\dfrac{18}{20}=\dfrac{30}{20}$

$\dfrac{x}{5}+\dfrac{9}{10}=\dfrac{3}{2}$

Subtract $\dfrac{9}{10}$ from both sides.

$\dfrac{x}{5}=\dfrac{3}{2}-\dfrac{9}{10}$

$\dfrac{x}{5}=\dfrac{15-9}{10}$

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