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3 years ago

Can you please help me with this that’ll you so much

Mathematics

1 answer:

Nana76 [90]3 years ago

4 0

Add the fractions together to find the portion who like basketball, soccer and football.

=1/3 + 1/8 + 5/12
need a common denominator (24)

=8/24 + 3/24 + 10/24
=21/24

simplify by 3
=7/8 like basketball, football & soccer

7/8 is the total for basketball, soccer and football. If 8/8 represents the whole class, then subtract 7/8 from 8/8 to find the number who like baseball.

=8/8 - 7/8
=1/8 of the remainder likes baseball

ANSWER: 1/8 of the students like baseball

Hope this helps! :)

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The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

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In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

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