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4 years ago

Find the area of the triangle.

Mathematics

1 answer:

madreJ [45]4 years ago

8 0

Start by finding the area of each smaller right triangle.
Right triangle area = (1/2)hb -> h = height & b = base
b = 4 & h = 3
(1/2)(4)(3) = 6
6*2 = 12 (there are two right triangles)
The area of the entire triangle is 12yd^2

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First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

Eduardo's definition of parallel lines is two lines that never meet. Is he correct? In two or more complete sentences, explain w

Ratling [72]

The definition of parallel lines is; two lines that are always the same distance apart and never touch. In order for two lines to be parallel, they must be drawn in the same plane, a perfectly flat surface like a wall or sheet of paper. ... Any line that has the same slope as the original will never intersect with it.

3 0

3 years ago

Read 2 more answers

What is 35223 divided by 5

Kazeer [188]

Answer: 7,044.6

Step-by-step explanation:

35223/5 = 7,044.6

7 0

3 years ago

Read 2 more answers

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