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zimovet [89]
3 years ago
14

What is the following product? (5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

Mathematics
2 answers:
Zina [86]3 years ago
8 0

Answer:

(5 square root 2-4 square root 3) (5 square root 2-4 square root 3)

=   98 - 40\sqrt{6}

Step-by-step explanation:

i) (5\sqrt{2} - 4\sqrt{3}) × (5√2 - 4√3)

=(5\sqrt{2} × 5\sqrt{2}) - (5\sqrt{2} × 4\sqrt{3}) - (4\sqrt{3} × 5\sqrt{2}) + (4\sqrt{3} × 4\sqrt{3})

= 50 - 20\sqrt{6} - 20\sqrt{6} + 48

= 98 - 40\sqrt{6}

masya89 [10]3 years ago
5 0

Answer:

98 - 40√6

Step-by-step explanation:

The words expression can be represented as follows:

(5√2 - 4√3) (5√2 - 4√3)

The question is to find the products .

(5√2 - 4√3) (5√2 - 4√3)

Multiply through to open the bracket

25 × 2 - 20√6- 20√6 + 16 × 3

50 - 20√6 - 20√6 + 48

50 - 40√6 + 48

50 + 48 - 40√6

98 - 40√6

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This is a right triangle with two congruent angles. so this is a isoceles right triangle or called a

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What much expression represents a rational number?
Pie

Answer:

\displaystyle \frac{2}{7}+\sqrt{121}

Step-by-step explanation:

<u>Rational Numbers</u>

A rational number is any number that can be expressed as a fraction

\displaystyle \frac{a}{b}, \ b\neq 0

for a and b any integer and b different from 0.

As a consequence, any number that cannot be expressed as a fraction or rational number is defined as an Irrational number.

Let's analyze each one of the given options

\displaystyle \frac{5}{9}+\sqrt{18}

The first part of the number is indeed a rational number, but the second part is a square root whose result cannot be expressed as a rational, thus the number is not rational

\pi + \sqrt{16}

The second part is an exact square root (resulting 4) but the first part is a known irrational number called pi. It's not possible to express pi as a fraction, thus the number is irrational

\displaystyle \frac{2}{7}+\sqrt{121}

The square root of 121 is 11. It makes the whole number a sum of a rational number plus an integer, thus the given number is rational

\displaystyle \frac{3}{10}+\sqrt{11}

As with the first number, the square root is not exact. The sum of a rational number plus an irrational number gives an irrational number.

Correct option:

\boxed{\displaystyle \frac{2}{7}+\sqrt{121}}

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