Answer:
True
Explanation:
Because they come across many challenges
The original milk sample contained 54000 cells per milliliter of the milk.
Plate count assay is used to identify the number of viable cells in a sample given. It is done by the serial dilution technique which is the step wise dilution of a substance in a sample. Serial dilution is followed by plating technique which helps in finding individual dilutions, finding serial dilutions and the number of organisms present in the original sample.
In the question, one-milliliter sample of the milk is diluted in a 1:10 dilution series and one milliliter of the third dilution tube is plated in a pour plate. After incubation, the plate shows 54 colonies. Third dilution is represented by 
. The formula used for the calculation of the number of organisms present in the original sample of milk is number of colonies growing on the plate x (1 x volume used to plate bacteria) x (1/dilution). By substituting the values given,
No. of organisms in the original milk sample
= 54 x (1 x 1ml) x (1/)
= 54 x 1 /
= 54000.
Answer:
TAA
Explanation:
<em>The triplet base sequence in DNA that is translated into a stop codon, whose corresponding tRNA anticodon, is AUU is given by </em><em>TAA.</em>
There are three stop codons in nature and these include UAG, UGA, and UAA. Out of all these codons, the one whose corresponding tRNA codon is AUU would be UAA stop codon.
<u>However, as a rule of thumb, only RNA contains uracil base instead of thymine in DNA. Hence the 'U' in UAA mRNA stop codon which refers to uracil is replaced by 'T' (thymine) in DNA. </u>
Therefore, UAA becomes TAA.
Answer: so whats the question
sorry if i failed to make it out
and
you typed that all in!!!
Explanation:
