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OlgaM077 [116]
3 years ago
5

Which element has two or more protons than iron (FE)?

Physics
2 answers:
uysha [10]3 years ago
6 0
I'm pretty sure the answer would be Nickel C 
barxatty [35]3 years ago
5 0
Nickel with 28 protons whereas iron has 26
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Suppose you calculated the speed of light in an unknown substance to be 4.00x10^8 m/s. How could you tell if you made an error i
Mice21 [21]

Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

6 0
2 years ago
A mercury barometer reads 745.0 mm on the roof of a building and 760.0 mm on the ground. Assuming a constant value of 1.29 kg/m3
Ipatiy [6.2K]

Answer:

The height of the building is 158.140 meters.

Explanation:

A barometer is system that helps measuring atmospheric pressure. Manometric pressure is the difference between total and atmospheric pressures. Manometric pressure difference is directly proportional to fluid density and height difference. That is:

\Delta P \propto \rho \cdot \Delta h

\Delta P = k \cdot \rho \cdot \Delta h

Where:

\Delta P - Manometric pressure difference, measured in kilopascals.

\rho - Fluid density, measured in kilograms per cubic meter.

\Delta h - Height difference, measured in meters.

Now, an equivalent height difference with a different fluid can be found by eliminating manometric pressure and proportionality constant:

\rho_{air} \cdot \Delta h_{air} = \rho_{Hg} \cdot \Delta h_{Hg}

\Delta h_{air} = \frac{\rho_{Hg}}{\rho_{air}} \cdot \Delta h_{Hg}

Where:

\Delta h_{air} - Height difference of the air column, measured in meters.

\Delta h_{Hg} - Height difference of the mercury column, measured in meters.

\rho_{air} - Density of air, measured in kilograms per cubic meter.

\rho_{Hg} - Density of mercury, measured in kilograms per cubic meter.

If \Delta h_{Hg} = 0.015\,m, \rho_{air} = 1.29\,\frac{kg}{m^{3}} and \rho_{Hg} = 13600\,\frac{kg}{m^{3}}, the height difference of the air column is:

\Delta h_{air} = \frac{13600\,\frac{kg}{m^{3}} }{1.29\,\frac{kg}{m^{3}} }\times (0.015\,m)

\Delta h_{air} = 158.140\,m

The height of the building is 158.140 meters.

5 0
3 years ago
Read 2 more answers
Which best explains how thermal energy is transferred when someone holds a hand above a fire?
Artyom0805 [142]
Heat rises therefore the heat from the fire rises up to your hand... i didnt have any answer choices to work with sorry
5 0
3 years ago
Read 2 more answers
A playground merry-go-round of radius r = 2.00 m has a moment of inertia = 250 ⋅ , and is rotating at 10.0 rev/min about a frict
bagirrra123 [75]

Answer:

330kgm^2

Explanation:

We are given that

Radius,r=2 m

Moment of inertia,I=250kgm^2

Angular velocity,\omega_1=10 rev/min

Mass of child,m=20 kg

We have to find the new moment of inertia of the merry go round.

New moment of inertia ,I'=mr^2+I

Using the formula

I'=20(2)^2+250

I'=80+250=330kgm^2

Hence, the new moment of inertia of the merry -go-round=330kgm^2

8 0
3 years ago
A student lifts a 50 pound (lb) ball 4 feet (ft) in 5 seconds (s). How many joules of work has the student completed?
Elis [28]

           Work = (weight) x (distance)

  Work = (50 lb) x (1 kg / 2.20462 lb) x (9.81 newton/kg)

                           x (4 feet) x (1 meter / 3.28084 feet)

           = (50 x 9.81 x 4) / (2.20462 x 3.28084)  newton-meter

           =        271.3 joules .

We don't need to know how long the lift took, unless we
want to know how much power he was able to deliver.

                   Power = (work) / (time)    

                               = (271.3 joule) / (5 sec)  =  54.3 watts .
________________________________________

The easy way:

         Work = (weight) x (distance)

                
  = (50 pounds) x (4 feet)  =  200 foot-pounds

Look up (online) how many joules there are in 1 foot-pound.

There are  1.356 joules in 1 foot-pound.

So  200 foot-pounds = (200 x 1.356) = 271.2 joules.

That's the easy way.
5 0
3 years ago
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