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Ivan
4 years ago
13

An aluminum sheet is compressed to a thickness of 2.0 microns. If each cubic centimeter of aluminum has a mass of 2.70 g, what i

s the mass of an aluminum sheet, in grams, if its total surface area is 5 m2
Physics
1 answer:
Nezavi [6.7K]4 years ago
6 0
We need to find the volume V of the sheet of aluminum that has a thickness t of t=2 micrometers and that is equal to t= 2*10^6 m and area A = 5 m². Volume V is:

V=A*t= 5*2*10^-6 = 1*10^-5 m³. 

Now we need to find the volume V in cm³:

1 m³ = 1 000 000 cm³ so 10^-5 m³ = 10 cm³. 

If 1 cm³ has a mass of 2.70 g then 10 cm³ has a mass of 27.0 grams.

So the correct answer is the mass of the aluminum sheet is m= 27 g or m=0.027 kg. 
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4 0
3 years ago
Gravitational potential energy is usually just written as
Elenna [48]

Gravitational potential energy is usually just written as GPE

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its position in a gravitational field. It is usually indicated with GPE.

Near the Earth's surface, the  GPE of an object is given by

GPE=mgh

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity near the surface

h is the heigth of the object above the surface

We notice that the GPE is directly proportional to the heigth above the ground, h: therefore, when the object is lifted from the ground, its GPE increases, while when it is lowered towards the ground, its GPE decreases.

Learn more about potential energy:

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3 0
4 years ago
A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s
ddd [48]

Answer:

The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant h = 6.626\times10^{−34}\ J.s

Speed of light c=2.998\times10^{8}\ m/s

Mass of electron m_{e}=9.109\times10^{-31}\ kg

Charge q=1.602\times10^{-19}\ C

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

E=m_{0}c^2

E=9.109\times10^{-31}\times(3\times10^{8})^2

E=8.198\times10^{-14}\ J

Energy in eV

E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}

E=512375\ eV

E=0.512\ MeV

The total energy of photon

TE=2(E+K.E)

TE=2(0.512+0.261)

TE=1.546\ MeV

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}

\lambda=8.036\times10^{-13}\ m

Hence, The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

7 0
3 years ago
The teacher measured the maximum height and the minimum height of the plastic duck above the screen as the wave passed. The teac
fenix001 [56]

The teacher measured the maximum height and the minimum height of ...

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3 years ago
A 3.0 kg rifle is held firmly by a 50.0 kg woman, initially standing still. A 0.06 kg bullet leaves the rifle muzzle with a velo
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Answer:

48kg

Explanation:

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7 0
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