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4 years ago

5

A student determines that a piece of an unknown material has a mass of 5.854 g and a volume of 7.57 cm3. What is the density of

the material?
Question 10 options:

A. 1.30 g/cm3

B. 0.39 g/cm3

C. 1.55 g/cm3

D. 0.77 g/cm3

1 answer:

daser333 [38]4 years ago

4 0

Answer is D. Is this the Domain quiz? Domain II?

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Converted to<br> Energy<br> Electricity powers the lights<br> for a building.

Slav-nsk [51]

Answer:

More than enough solar energy (8.2 million quad BTUs, 1 quad = 2.9 x1011 kWh) hits Earth's surface each year to meet all of societies' needs. Currently we use about 400 quads per year to run our society. Good building design allows passive use of sunlight to heat homes. Simple solar collectors are used to heat water and cook food. As useful as it is for these purposes, thermal energy from sunlight is still a low quality energy compared to electricity. Computers, most machinery, light bulbs, subway trains, and much more all require electricity. It is possible to turn thermal energy from the sun into electricity. In this unit we will examine how.

. We will also examine how to make electricity directly from light using the photovoltaic cells.

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3 years ago

Two children weighing 17 and 25 kilograms are sitting on opposite sides of a seesaw, both 2 meters from the axis of rotation. wh

Over [174]

The principle of moments states that for a system at equilibrium the clockwise moments is equal to the anticlockwise moments.
Moments is given by force × perpendicular distance
Moments one one side of the seesaw will be 340Nm and on the other will be 500Nm, for balanced or equilibrium to be achieved the two moments should be equal.
Difference is 160 Nm, thus with a child 10 kg to balance the system, then,
Distance will be 16 nm/ 100N = 1.6 m
Threfore, a child of 10 kg should sit at a distance of 1.6m from the pivot on the side with 17 kg child for the system to balance.

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4 years ago

A package is dropped from the height of 100 m and falls freely. How fast will the package be traveling when it hits the ground?

ki77a [65]

Answer:

<em>The package will be traveling at 44.3 m/s when it hits the ground</em>

Explanation:

<u>Free Fall Motion</u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is $g = 9.8 m/s^2$ .

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

$\displaystyle y=\frac{gt^2}{2}$

If we know the height h from which the object was dropped, we can find the time it takes fo hit the ground:

$\displaystyle t=\sqrt{\frac{2h}{g}}$

The package was dropped from h=100 m, thus the time taken to reach the ground is:

$\displaystyle t=\sqrt{\frac{2(100)}{9.8}}$

$t = 4.52~s$

The final speed is now calculated:

$vf=9.8*4.52$

$vf=44.3~m/s$

The package will be traveling at 44.3 m/s when it hits the ground

7 0

3 years ago

Which single force acts on an object in freefall?

jok3333 [9.3K]

It has to be a)gravity

4 0

3 years ago

Read 2 more answers

A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi

Airida [17]

Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

$F_{net} = F_{1} + F_{2} = 0$

So,

$\frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0$

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

$\frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}$

On dividing both sides of the equation by G.m.M, we get the following.

$\frac{1}{(1 - x)^{2}} = \frac{3}{x^{2}}$

$x^{2} = 3 - 6x + 3x^{2}$

0 = $3 - 6x + 2x^{2}$

Using the formula, $\frac{-b \pm \sqrt{(b)^{2} - 4ac}}{2a}$ the value of x comes out to be equal to +2.37 (not usabale) and -0.634 (usable).

Hence, we can conclude that the third mass will be located 0.634 meters away from the 3 m mass.

7 0

3 years ago