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Yuki888 [10]
3 years ago
5

Worth 10pts if someone can help!

Mathematics
2 answers:
charle [14.2K]3 years ago
7 0

Answer:

y=-x

I found the points then simplified it down

Aloiza [94]3 years ago
3 0

Answer:

hmm maybe trying using 2y=5x-2

Step-by-step explanation:

how i came to this was just looking at point y which was just 2 and then since point x was at 5,-2 all i did was simply it into 2y=5x-2

maybe that's the answer if it is can i get brainlist ?! pretty please if not let me know so i can see what i got wrong

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Answer:

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Step-by-step explanation:

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3 years ago
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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
Delicious77 [7]

Answer:

(1)Equivalence Relation

(2)Not Transitive, (0,3) is missing

(3)Equivalence Relation

(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
  • Symmetry: \forall x,y \in A, $if x \rightarrow y,$ then y \rightarrow x
  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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Number of times it stopped in Section-2: 36

Total number of times you tried it:  (20 + 36 + 24)  =  80

Experimental probability of Section-2  =  36/80 = 9/20  =  45%
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