We want to recast the equation into the standard form equation for a circle centered at (h, k) with radius r. That equation is
... (x -h)² + (y -k)² = r²
Start by completing the square for both x-terms and y-terms.
... x² - 4x + y² + 4y = k
To do that, add the squares of half the coefficients of the x- and y-terms.
... x² - 4x + (-2)² + y² + 4y + 2² = k + (-2)² + 2²
... (x -2)² + (y +2)² = k + 8 = r² . . . . . this is now equal to the square of the radius, so we have
... k + 8 = 6² = 36
Subtracting 8 gives
... k = 28 . . . . . . . matches selection D)
Answer:
Step-by-step explanation:
- A) x⁶ + 27y⁹ = (x²)³ + (3y³)³ - sum of cubes
- B) 3x⁹ - 64y³ - the first term is not a cube
- C) 27x¹⁵ - 9y³ - the second term is not a cube
- D) 125x²¹- 64y³ = (5x⁷)³ - (4y)³ - difference of cubes
Correct option is the last one
Answer:
which one?
Step-by-step explanation:
Answer:
idk
Step-by-step explanation:
Answer:
Isosceles triangle
Step-by-step explanation:
Length AB
√(4 - 2)² + (7 - 2)²
√2² + 5²
√4 + 25
√29
Length AC
6 - 2 = 4
Length BC
√(6 - 4)² + (2 - 7)²
√2² + (-5)²
√4 + 25
√29
Length AB and BC is the same.
Length AC is the longest side.
Therefore, it is an isosceles triangle.
