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jolli1 [7]
3 years ago
6

Please help with algebra 2

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

- 8 or A

Step-by-step explanation:

Problem 1

First of all, you could write f(x) in terms of its x intercepts.

x = - 2

x + 2 = 0

x= 1

x - 1 = 0

x = 4

x - 4 = 0

So f(x) = (x - 4)(x - 1)(x + 2)

The division to find the remainder can be done expanding this further and doing a synthetic division on it, but the easier way is just to put 2 in for x. That is because x - 2 is turned into 0 by making x = 2

f(2) = (2 - 4)(2 - 1)(2 + 2)

f(2) = (-2)(1)(4)

f(2) = - 8

=====================

The expanded form of this question is f(x) = x^3 - 3x^2 -  6x  +  8

You could do this with synthetic division. It will give you the same answer.

2 ||    1     -3     -6      8

               2      -2    -16

=========================

        1      -1       -8    -8

The remainder is -8

Answer: A


which gives you exactly the same answer. (x - 2) into x^3 - x^2 - 16x + 16 will leave a remainder of  - 12

Problem 2


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A line is perpendicular to y = - x - 2 and intersects the point (-5, 10)
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Answer:

y = x + 15

Step-by-step explanation:

If two lines are perpendicular to each other, they have opposite slopes.

The first line is y = - x - 2. Its slope is -1. A line perpendicular to this will have a slope of 1.

Plug this value (1) into your standard point-slope equation of y = mx + b.

y = 1x + b or y = x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (-5, 10). Plug in the x and y values into the x and y of the standard equation.

10 = (-5) + b

Simplify.

10 = -5 + b

Now, add 5 to both sides to isolate b.

15 = b

Plug this into your standard equation.

y = x + 15

This equation is perpendicular to your given equation (y = -x - 2) and contains point (-5, 10)

Hope this helps!

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Step-by-step explanation:

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