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3 years ago

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2 and 32 ten thousandths in standard form

1 answer:

RideAnS [48]3 years ago

8 0

2 ten thousands :20,000
32 ten thousands: 320,000

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A solution is tested and found to have a pH of 1. The solution is A. strongly acidic. B. strongly basic. C. weakly basic. D. wea

Trava [24]

When a solution has Ph of 1 in it

it is highly acidic

So your answer would be A) Strongly acidic

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3 years ago

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A line segment that has both endpoints on the circumference

AlexFokin [52]

Answer:

A chord

Step-by-step explanation:

By the definition of a chord, it is a line segment whose endpoints lie on the circle, (and in this case circle is meant by the set of points equidistant from a center point, or as an algebraic term: circumference)

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3 years ago

Find the equation of the line that has a slope of 3 and passes through the point (-5,4)

Ipatiy [6.2K]

We can use point-slope form (since we have the slope, and 1 ordered pair)

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3 years ago

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Suppose that the epidemiologist wants to re-estimate the population proportion and wishes for her 95% confidence interval to hav

Svetllana [295]

Answer:

She needs a sample of at least 385.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

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So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample should she take to achieve this?

She needs a sample of size at least n.

n is found when M = 0.04.

We do not know the true population proportion, so we use $\pi = 0.5$ , which is the case for which we are going to need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.05\sqrt{n} = 1.96*0.5$

Dividing both sides by 0.05

$\sqrt{n} = 19.6$

$(\sqrt{n})^{2} = 19.6^{2}$

$n = 384.2$

Rounding up

She needs a sample of at least 385.

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