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Anvisha [2.4K]
3 years ago
11

2 and 32 ten thousandths in standard form

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0
2 ten thousands :20,000
32 ten thousands: 320,000
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A man jogs from his home to the nearst market 25km away jogs at an average speed 5km 1h. how long does it taken him to reach the
mr_godi [17]

Answer:

1/5

Step-by-step explanation:

first write the formula of average speed

  • 2) then equate the values of given question
  • 3) you will find the solution

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3 years ago
Help!!Need help please help me
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 8x-6y=-96  add to this -4 times the second equation...
-8x-12y=-48
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8x-48=-96

8x=-48

x=-6

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(-6,8)
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3 years ago
Hannah mixed 6.83 lb of almonds with 3.57 lb of peanuts.After filling up 6 bags that were the same size with the mixture, she ha
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3 0
2 years ago
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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
4 years ago
a foreman must order enough sod to cover a dirt area 36 feet wide by 28 feet long. each piece of sod is 3 feet long and 12 inche
Andrews [41]

If we divide the area we have to cover by the area of a piece, we will get the number of pieces needed:

n=\dfrac{\text{dirt area}}{\text{piece area}}=\dfrac{36\times 28}{3\times 12} = \dfrac{36\times 28}{36}=28

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3 years ago
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