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Wewaii [24]
3 years ago
9

What are the intercepts of x^2+y-9=0

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

Zeros

x = -3   point (-3 ,0)

x = 3   point (3 ,0)

Step-by-step explanation:

Using a graphing calculator, we can easily check the intercepts of the equation

y  = -x^2 +9

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3 years ago
Y = -4x + 8<br> Y=3/5x - 6/5
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Answer:

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Step-by-step explanation:

Rewrite equations:

y=−4x+8;y=

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5

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Step: Solvey=−4x+8for y:

y=−4x+8

Step: Substitute−4x+8foryiny=

3

5

x+

−6

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:

y=

3

5

x+

−6

5

−4x+8=

3

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x+

−6

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−4x+8+

−3

5

x=

3

5

x+

−6

5

+

−3

5

x(Add (-3)/5x to both sides)

−23

5

x+8=

−6

5

−23

5

x+8+−8=

−6

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+−8(Add -8 to both sides)

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−46

5

−23

5

x

−23

5

=

−46

5

−23

5

(Divide both sides by (-23)/5)

x=2

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y=−4x+8

y=(−4)(2)+8

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