Answer:
x=-2
y=14
Step-by-step explanation:
-7x=4x+22
-11x=22
x=-2
y=-7(-2)
y=14
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Using the formula for the circumference of a circle:
2 x 100 x 3.14=628ft
Given:
The figure.
To find:
The segment bisector of MN and value of MN.
Solution:
From the given figure it is clear that ray RP,i.e., 
is the segment bisector of MN because it divides segment MN in two equal parts.
Now,
Since, is the segment bisector of MN, therefore,
Therefore, the length of MN is 
.
Answer:
60mm(millimeters)
Step-by-step explanation:
The bar for June goes up to the 60 mark.
