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3 years ago

What is (3x^4+2x^2-6) subtracted from (4x^4+2x^2-6)

Mathematics

1 answer:

Tatiana [17]3 years ago

4 0

Answer:

The answer is -x^4, Good Luck!

Step-by-step explanation:

(3x^4+2x^2-6) - (4x^4+2x^2-6) = -x^4

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Point a is at (-7,-7) and m is at (-6,-1) what are the coordinates of point b

AlekseyPX

Answer:

The coordinates of point b are (-5,5).

Step-by-step explanation:

Given:

Point a is at (-7,-7) and m is at (-6,-1).

So, to find the coordinates of point b.

Let a (-7,-7) be $(x_{1},y_{1})$ , m (-6,-1) and b $(x_{2} ,y_{2})$ .

Now, putting the formula to get the coordinates:

$m=\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2}$

⇒ $(-6,-1)=\frac{-7+x_{2}}{2} , \frac{-7+y_{2}}{2}$

So, here we will make two equations to find the value of $x_{2} andy_{2}$ :

$-6=\frac{-7+x_{2}}{2}$

multiplying both sides by 2

⇒ $-12=-7+x_{2}$

⇒ $-5=x_{2}$

And, now same method for getting the value of $y_{2}$ .

$-1=\frac{-7+y_{2}}{2}$

multiplying both sides by 2

⇒ $-2=-7+y_{2}$

⇒ $5=y_{2}$ .

The value of $(x_{2} ,y_{2})$ = $(-5,5)$ .

Therefore, the coordinates of point b are (-5,5).

4 0

3 years ago

In a class 28 of students, 5 have a cat and 21 have a dog. There are 4 students who do not have a cat or a dog. What is the prob

Sergeeva-Olga [200]

Answer:

15 have only a dog

5 have a dog and a cat

9 have only a cat

Step-by-step explanation:

20 + 14 = 34, there there are only 29 students, so 34 - 29 or 5 have both a dog and a cat

15 have only a dog

5 have a dog and a cat

9 have only a cat

6 0

3 years ago

Gabriel earned $238.40 at His job when he word for 16 hours what was his hourly wage in dollars per hour?

Fiesta28 [93]

Answer:

$14.9

Step-by-step explanation:

238.40 / 16 = $14.9 hourly

4 0

2 years ago

Read 2 more answers

What is the relationship between exponentials and logarithms? How can you use these to solve equations? Provide an example in yo

Sveta_85 [38]

Answer:

Exponentials and logarithms are inverses of each other.

Step-by-step explanation:

Exponentials and logarithms are inverses of each other.

For logarithmic function:

Domain = $\left ( 0,\infty \right )$ , Range = $\left ( -\infty ,\infty \right )$

Vertical asymptote is y - axis.

x - intercept is (1,0)

For exponential function:

Domain = $\left ( -\infty ,\infty \right )$ , Range = $\left ( 0,\infty \right )$

Horizontal asymptote is x - axis.

y- intercept is (0,1)

Both exponential and logarithmic functions are increasing.

For example:

Solve: $\log x=\frac{\log 5+\log 3}{\log 3^2}$

$\log x=\frac{\log 5+\log 3}{\log 3^2}\\\log x=\frac{\log (5\times 3)}{2\log 3}\,\,\left \{ \because \log (ab)=\log a+\log b\,,\,\log a^b=b\log a \right \}\\=\frac{\log 15}{2\log 3}$

$\Rightarrow \log x=\frac{\log 15}{2\log 3}\\\Rightarrow x=e^{\frac{\log 15}{2\log 3}}\,\,\left \{ \because \log x=y\Rightarrow x=e^y \right \}$

4 0

3 years ago

Traveling math word problem - thank you! :)

Anni [7]

We are given:

car and train leave at the same time

average velocity of car = 50 miles/hour

average velocity of train = 70 miles/hour

train arrives 2 hours early

Assuming variables and making equations!

let the time taken by the train = t hours

since the car arrived late, it took more time as compared to the train

time taken by the car = t + 2 hours

since the distance from Pasadena to Sacramento doesn't change, both the vehicles covered the same distance, d

Distance travelled by the car:

d = 50 $\frac{miles}{hour}$ * (t+2) hours [distance = velocity * time]

d = 50(t+2) miles

rewriting in terms of t

$t = \frac{d-100}{50}$

Distance travelled by the train:

d = 70 $\frac{miles}{hour}$ * t hours

d = 70t miles

rewriting in terms of t

$t = \frac{d}{70}$

now we have two expressions for t, both of which are equal because t is just the time taken by the train

Finding the distance:

$t = \frac{d-100}{50}$

$t = \frac{d}{70}$

because t is the same:

$\frac{d-100}{50} = \frac{d}{70}$

$\frac{d-100}{5} = \frac{d}{7}$

7(d - 100) = 5(d)

7d - 700 = 5d

(7d - 5d) - 700 = 0 [subtracting 5d from both sides]

2d = 700 [adding 700 on both sides]

d = 350 miles [dividing both sides by 2]

The distance between Pasadena and Sacramento is 350 miles!

7 0

2 years ago