Answer:
Explanation:
From the given information:
mass = 3.42 kg = 3420 g
molar mass of
= 59 g
Number of moles of ![C_3H_7NH_2 = \dfrac{mass (in gram) }{molar mass}](https://tex.z-dn.net/?f=C_3H_7NH_2%20%3D%20%5Cdfrac%7Bmass%20%28in%20gram%29%20%7D%7Bmolar%20mass%7D)
Number of moles of ![C_3H_7NH_2 = \dfrac{3420 \ g }{59 \ g}](https://tex.z-dn.net/?f=C_3H_7NH_2%20%3D%20%5Cdfrac%7B3420%20%5C%20g%20%7D%7B59%20%5C%20g%7D)
= 57.966
number of hydrogen atoms present = ![n \times N_A](https://tex.z-dn.net/?f=n%20%5Ctimes%20N_A)
where;
![N_A = avogadro's \ constant = 6.022 \times 10^{23}](https://tex.z-dn.net/?f=N_A%20%3D%20avogadro%27s%20%5C%20constant%20%3D%206.022%20%5Ctimes%2010%5E%7B23%7D)
number of hydrogen atoms present ![=9 \times 57.966 \imes 6.022 \times 10^{23}](https://tex.z-dn.net/?f=%3D9%20%5Ctimes%2057.966%20%5Cimes%206.022%20%5Ctimes%2010%5E%7B23%7D)
![\mathbf{= 3.14 \times 10^{26}}](https://tex.z-dn.net/?f=%5Cmathbf%7B%3D%203.14%20%5Ctimes%2010%5E%7B26%7D%7D)
Non-metal are the elements that can accept electrons,this creates a larger positive charge in the nucleus than the negative charge.
Due to this attraction, electron cloud shrinks or come closer to nucleus as the result of opposite charge and become ion .
Hence, the atomic radius of a non-metal<span> is generally smaller than the </span>ionic radius<span> of the same element.</span>
1297 grams of ore are needed to obtain 454.0 grams of Fe.
As the iron ore sample if found to be 35 percentage by mass
It means 35g of iron is present in 100g of ore.
1g of iron is present in 100/35 g of ore
And 454.0 g of iron is present in 100 × 454 / 35
= 1297.14 or 1297 grams (approx.)
The mass percent is calculated by dividing the mass of the compound or solute by the mass of the element or solute. A percent is obtained by multiplying the result by 100.
The formula for an element's percentage in a compound is as follows:
mass percent is calculated by multiplying the mass of the element in one mole of the compound by one hundred.
A solution follows this formula:
(gm of solute / gm of solute plus solvent) × 100 equals mass percent.
or
(gm of solute/grams of solution) x 100 Equals mass percent
Hence, 1297 grams of ore are needed to obtain 454.0 grams of Fe.
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The element that was oxidized is carbon, as it’s oxidation state increased (electrons were lost) from +2 (in the reactants) to +4 (in the products). The element that was reduced is nitrogen, as it gained electrons and went from a +2 oxidation state (reactants) to a 0 oxidation state (products). Since the carbon was oxidized and it’s electrons were used to reduce the nitrogen, carbon is the reducing agent.
<span>PV=nRT Since P, V and R are constant, when T goes up, n must go down by the same factor </span>1:4