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hoa [83]
3 years ago
10

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

n explanation for each answer.
2CO + 2NO -> 2CO2 + N2
Chemistry
1 answer:
GREYUIT [131]3 years ago
7 0
The element that was oxidized is carbon, as it’s oxidation state increased (electrons were lost) from +2 (in the reactants) to +4 (in the products). The element that was reduced is nitrogen, as it gained electrons and went from a +2 oxidation state (reactants) to a 0 oxidation state (products). Since the carbon was oxidized and it’s electrons were used to reduce the nitrogen, carbon is the reducing agent.
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using the equation 2h2+o2-->2h2o, if 192g of oxygen are produced, how many grams of hydrogen must react with it
UkoKoshka [18]
The balanced chemical reaction is:

<span>2H2+O2-->2H2O
</span>
To determine the mass of hydrogen that is needed, we need use the initial amount of oxygen and relate it to hydrogen from the reaction given. We do as follows:

192 g O2 ( 1 mol O2 / 32 g O2) ( 2 mol H2 / 1 mol O2 ) ( 2.02 g H2 / 1 mol H2 ) = 24.24 g H2
4 0
3 years ago
Does sodium (Na) and argon (Ar) on the periodic table have similar properties? Explain in terms of location on the periodic tabl
iVinArrow [24]

Sodium (Na) and Argon (Ar) on the periodic table does not have similar properties.

PERIODIC TABLE:

  • Periodic table is the organized table that showcases the position of elements. The periodic table is organized into groups and periods.

  • Groups of the periodic table is in a vertical format labeled 1 - 7 while the period is in a horizontal format labeled 1 - 7.

  • Elements in the same group have the same number of valence electrons and hence, possess similar chemical properties.

  • Sodium (Na) belongs to group 1 while argon is a noble gas, hence, they are not in the same group of the periodic table and cannot have same properties.

Learn more at: brainly.com/question/24089206?referrer=searchResults

6 0
2 years ago
in the laboratory a student dilute 13.3 ml of a 10.8 m hcl solution to a total of 300.0 ml what is the concentration of the dilu
krek1111 [17]

<u>Answer:</u> The concentration of the diluted solution is 0.4788M

<u>Explanation:</u>

To calculate the concentration of the diluted solution, we use the following equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of HCl solution

M_2\text{ and }V_2 are the molarity and volume of the diluted HCl solution.

We are given:

M_1=10.8M\\V_1=13.3mL\\M_2=?M\\V_2=300mL

Putting values in above equation, we get:

10.8\times 13.3=M_2\times 300\\\\M_1=0.4788M

Hence, the concentration of the diluted solution is 0.4788M

6 0
3 years ago
As an EPA scientist studying catalytic converters and urban smog, you want to find Kc for the following reaction: 2NO2(g) ⇋ N2(g
Bas_tet [7]

Answer:

Kc = 4.774 * 10¹³

Explanation:

the desired reaction is

2 NO₂(g) ⇋ N₂(g) + 2 O₂(g)

Kc =[N₂]*[O₂]² /[NO₂]²

Since

1/2 N₂(g) + 1/2 O₂(g) ⇋ NO(g)

Kc₁= [NO]/(√[N₂]√[O₂]) →  Kc₁²= [NO]²/([N₂][O₂])

and

2 NO₂(g) ⇋ 2 NO(g) + O₂(g)

Kc₂= [NO]²*[O₂]/[NO₂]² →  1/Kc₂= [NO₂]²/([NO]²[O₂])

then

Kc₁²* (1/Kc₂) = [NO]²/([N₂]*[O₂]) *[NO₂]²/([NO]²[O₂])  = [NO₂]²/([N₂]*[O₂]²) = 1/Kc

Kc₁² /Kc₂ = 1/Kc

Kc= Kc₂/Kc₁² =1.1*10⁻⁵/(4.8*10⁻¹⁰)² = 4.774 * 10¹³

3 0
2 years ago
What type(s) of intermolecular forces are expected between ch3conhch3 molecules?
hoa [83]
Hydrogen bonds.
________________
3 0
2 years ago
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