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irga5000 [103]
3 years ago
12

As you move from left to right across a period on the periodic table the size of an atom will

Chemistry
2 answers:
ANTONII [103]3 years ago
7 0

Answer:

Moving from left to right across a period, the atomic radius decreases. The nucleus of the atom gains protons moving from left to right, increasing the positive charge of the nucleus and increasing the attractive force of the nucleus upon the electrons.

Anastasy [175]3 years ago
7 0

Answer:the atomic radius will decrease.The nucleus of the atom will gain protons moving from left to right

Explanation:

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Why is Galileo Galilei impotant?
Rainbow [258]

Answer:

He provided a number of scientific insights that laid the foundation for future scientists. He also improved telescope that helped further the understanding of the world and universe.

Explanation:

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3 years ago
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How many atoms are in 294 g of copper?
mote1985 [20]

Answer

2.1 x 10 ^23

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3 years ago
A friend tells you that plants grow and gain mass only because of the nutrients they pull out of the soil. It this statement tru
Nutka1998 [239]
The statement that the friend made is not true. most of the mass of the plant is from carbon. the carbon comes from carbon dioxide which is used during photosynthesis. the left over carbon from photosynthesis is used to to help the plant gain mass. there is a process for this which is called cellular respiration
5 0
3 years ago
A chemist fills a reaction vessel with 0.750 M lead (II) (Pb2+) aqueous solution, 0.232 M bromide (Br) aqueous solution, and 0.9
Ronch [10]

Answer:

The free energy = -20.46 KJ

Explanation:

given Data:

Pb²⁺ = 0.750 M

Br⁻ = 0.232 M

R = 8.314 Jk⁻¹mol⁻¹

T = 298K

The Gibb's free energy is calculated using the formula;

ΔG = ΔG° + RTlnQ -------------------------1

Where;

ΔG° = standard Gibb's freeenergy

R = Gas constant

Q = reaction quotient

T = temperature

The chemical reaction is given as;

Pb²⁺(aq) + 2Br⁻(aq) ⇄PbBr₂(s)

The ΔG°f are given as:

ΔG°f (PbBr₂)  = -260.75 kj.mol⁻¹

ΔG°f (Pb²⁺)   = -24.4 kj.mol⁻¹

ΔG°f (2Br⁻)    = -103.97 kj.mol⁻¹

Calculating the standard gibb's free energy using the formula;

ΔG° = ξnpΔG°(product) - ξnrΔG°(reactant)

Substituting, we have;

ΔG° =[1mol*ΔG°f (PbBr₂)] - [1 mol *ΔG°f (Pb²⁺) +2mol *ΔG°f (2Br⁻)]

ΔG° =(1 *-260.75 kj.mol⁻¹) - (1* -24.4 kj.mol⁻¹) +(2*-103.97 kj.mol⁻¹)

      = -260.75 + 232.34

     = -28.41 kj

Calculating the reaction quotient Q using the formula;

Q = 1/[Pb²⁺ *(Br⁻)²]

   = 1/(0.750 * 0.232²)

  = 24.77

Substituting all the calculated values into equation 1, we have

ΔG = ΔG° + RTlnQ

ΔG = -28.41 + (8.414*10⁻³ * 298 * In 24.77)

     = -28.41 +7.95

    = -20. 46 kJ

Therefore, the free energy of reaction = -20.46 kJ

8 0
3 years ago
Calculate the number of atoms in 2.0g of hydrogen atoms?
Jobisdone [24]
First you calculate how many moles there are in 2.0 grams of hydrogen (H2) atoms.
Hydrogen has a relative atomic mass (RAM) of 1 g/mol, but there are 2 hydrogen atoms: 1 x 2 = 2 g/mol

To work out how many moles there are,
use the formula: n(moles) = mass ÷ molar mass
n(moles) = 2 grams ÷ 2 g/mol = 1 mol

Then use Avogadro's Constant : 6.023 x 10^23
= 1 x 6.023 x 10^23
= 6.023 x 10^23

Final step is to multiply it by the number of atoms, in this case there are 2.
= 6.023 x 10^23 x 2
= 12.046 x 10^23
= 1.205 x 10^24

that ^ should be your final answer

have a great day :)

4 0
3 years ago
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