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allochka39001 [22]
4 years ago
9

I need help please!!!!??

Mathematics
1 answer:
allochka39001 [22]4 years ago
4 0

Answer:

<h2>n < 43</h2>

Step-by-step explanation:

n + 19 < 62           <em>subtract 19 from both sides</em>

n + 19 - 19 < 62 - 19

n < 43

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Ann [662]

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Answer:

  x = 12

Step-by-step explanation:

We can find x using either the measure of angle B, or the measure of angle A.

Using A, we have ...

  48 = x^2 -8x

Adding 16 completes the square:

  64 = x^2 -8x +16 = (x -4)^2

Then the positive solution is ...

  √64 = x -4

  x = 4 +8 = 12

The triangles are similar when x=12.

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<em>Check</em>

We expect angle B to be 84° when x=12:

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Find integrate (1/(xsqrt(1+(lnx)^2)),1,e,x) ...?
prohojiy [21]
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as 

<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>

<span>Next, complete the square. </span>

<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>

<span>Also, for the x in the numerator </span>

<span>x = x + 1/2 - 1/2. </span>

<span>So </span>

<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>

<span>Integrate term by term to get </span>

<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>

<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>

<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>

<span>= 2 √(x) ln(x) - √(x) + C. </span>

<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>

<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>

<span>= arctan(e^x) + C.</span>
4 0
4 years ago
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