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allochka39001 [22]
4 years ago
9

I need help please!!!!??

Mathematics
1 answer:
allochka39001 [22]4 years ago
4 0

Answer:

<h2>n < 43</h2>

Step-by-step explanation:

n + 19 < 62           <em>subtract 19 from both sides</em>

n + 19 - 19 < 62 - 19

n < 43

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Diagram 2 shows a piece of rectangular card in grey colour
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Solution:

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x + 5  \: cm

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7 \: cm

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so, we have-

(x + 5) \times 7 \: cm^{2}  \\ 7x + 35 \: cm^{2}

we also have given the length of ribbon-

7 \: cm

and, width-

y \: cm

so, area of the ribbon is-

length×width

7 \times y \: cm^{2}  \\ 7y \: cm^{2}

now the area of shaded gray region will be-

7x + 35 - 7y

Hence, the required expression would the above expression.

6 0
3 years ago
Can u help with the bonus
Reil [10]

The sum of the interior and exterior angle need to equal 180 degrees.

Let the exterior angle = X

You are told the interior angle = 38x +24

Now you have x + 38x +24 = 180

Combine like terms:

39x +24 = 180

Subtract 24 from each side:

39x = 156

Divide both sides by 39:

x = 156 / 39

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7 0
3 years ago
Read 2 more answers
How mang feet are in 3.76 km? Show ur solution
Zina [86]

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3 0
3 years ago
A coin is tossed three times. An outcome is represented by a string of the sort HTT (meaning a head on the first toss, followed
Ivanshal [37]

Answer:

Step-by-step explanation:

In this question, the sample space contains 8 elements and has been given as;

          HHT HHH THH HTH HTT TTT TTH THT

1. For event A:

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Pr(alternating tail and head (with either coming first)) = \frac{4}{8}

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2. For event B:

Outcomes of no tails on the first two tosses = HHT HHH

                                                   = 2 outcomes

Pr (No tails on the first two tosses) = \frac{2}{8}

                                            = \frac{1}{4}

For event C:

Outcomes of a tail on both the first and the last tosses = THT TTT

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Pr(A tail on both the first and last tosses) = \frac{2}{8}

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3 0
3 years ago
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Alik [6]
What’s the question???
8 0
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