Answer:
A) Magma emplacement
Explanation:
Sedimentary structures forms during deposition of sediments. It can also form after sediments have been deposited. Sedimentary structures can only be found in sedimentary rocks. Some examples include mud cracks, ripple marks, cross stratification, potholes, etc
Magma emplacement is an igneous process which describes the different mechanisms by which magma can be emplaced. It is only typical of igneous rocks.
Nitric acid (NHO3) because plants need nitrogen to survive, hope this helped.
The question is incomplete! The complete question along with answer and explanation is provided below.
Question:
A student bikes to school by traveling first 1.00 miles north, then 0.500 miles west and finally 0.200 miles south.
If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance db would the bird cover
Given Information:
distance towards north = dn = 1.00 mi
distance towards west = dw = 0.500 mi
distance towards south = ds = 0.200 mi
Required Information:
distance covered by bird = db = ?
Answer:
distance covered by bird = 0.94 miles
Explanation:
As you can see in the attached image, by applying the Pythagoras theorem,
db = √(dn - ds)² + dw²
db = √ (1.0 - 0.20)² + 0.50²
db = √ 0.80² + 0.50²
db = 0.94 miles
Therefore, the bird would cover a distance of 0.94 miles
The definition of a scale of 1: 166 will mean that the scale of 1 in the model will be equivalent to 166 times the measurement in the real model, therefore we will have that the height would be 166 times smaller than the 179m given:
![h = \frac{179m}{166} = 1.078m = 107.8cm](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B179m%7D%7B166%7D%20%3D%201.078m%20%3D%20107.8cm)
The same for the diameter,
![\phi = \frac{48m}{166}= 0.2891m = 28.91cm](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cfrac%7B48m%7D%7B166%7D%3D%200.2891m%20%3D%2028.91cm)
The volume of a cylinder is given as
![V = (\pi r^2)(h)](https://tex.z-dn.net/?f=V%20%3D%20%28%5Cpi%20r%5E2%29%28h%29)
![V = (\pi (\frac{d}{2})^2)(h)](https://tex.z-dn.net/?f=V%20%3D%20%28%5Cpi%20%28%5Cfrac%7Bd%7D%7B2%7D%29%5E2%29%28h%29)
![V = (\pi (\frac{ 28.91}{2})^2)(107.8)](https://tex.z-dn.net/?f=V%20%3D%20%28%5Cpi%20%28%5Cfrac%7B%2028.91%7D%7B2%7D%29%5E2%29%28107.8%29)
![V = 70762.8cm^3](https://tex.z-dn.net/?f=V%20%3D%2070762.8cm%5E3)
Therefore the volume would be ![V = 70762.8cm^3](https://tex.z-dn.net/?f=V%20%3D%2070762.8cm%5E3)
The answer is C because its shiny