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Varvara68 [4.7K]

2 years ago

9

two charges separated a distance of 1.0 meter exert a 1.0-N force on each other If the charges are pushed to a separation of 1/4

meter the force of each charge would be?

1 answer:

Effectus [21]2 years ago

8 0

Newtons of force is 20

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${\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\$

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<h3>☯ <u>By using formula of Lens</u> </h3>

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$\dashrightarrow\:\: {\boxed{\sf{\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}}}}$

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$\dashrightarrow\:\: \sf{\dfrac{1}{v}+\dfrac{1}{15}=\dfrac{1}{10}}$

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$\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{15}}$

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$\dashrightarrow\:\: \sf{\dfrac{1}{v} = \dfrac{1}{30}}$

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<h3>☯ <u>Now, Finding the magnification </u></h3>

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$\dashrightarrow\:\: \sf{ m = \dfrac{-30}{-15}}$

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$\dashrightarrow\:\: \sf{m = -2}$

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<h3>☯ <u>Hence</u>, $\\$ </h3>

$\:\:\:\:\star\:\:\:\sf{Image \ distance = 30 \ cm}$

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