Ask question

Ask question

All categories

4 years ago

5

The figure below shows several equipotential lines each labeled by its potential in volts. The distance between the lines of the

square grid represents 3.00 cm.

1 answer:

Mrrafil [7]4 years ago

7 0

I dont know this stuff i just want my poits

You might be interested in

Two wheels with fixed hubs, each having a mass of 1kg , start from rest, and forces are applied: F1= 1 N to the first wheel and

irina [24]

Answer:

2N

Explanation:

$m = m_1 = m_2 = 1 kg$

The torques generated by tangential forces on the 2 wheels are

$T_1 = F_1R_1 = 1*0.5 = 0.5 Nm$

$T_2 = F_2R_2 = F_2*1 = F_2 Nm$

According to Newton's 2nd law, the angular accelerations generated by these torque would be

$\alpha_1 = \frac{T_1}{I_1} = \frac{0.5}{mR_1^2} = \frac{0.5}{1*0.5^2} = 2 rad/s^2$

$\alpha_2 = \frac{T_2}{I_2} = \frac{F_2}{mR_2^2} = \frac{F_2}{1*1^2} = F_2 rad/s^2$

For the 2nd wheel to have the same angular acceleration, its force must be

$\alpha_1 = \alpha_2$

$2 = F_2$

$F_2 = 2N$

6 0

3 years ago

A car with an initial speed of 4.30 m/s accelerates at a rate of 3 ms^2. What is the car's speed after 5 s?

Lorico [155]

Answer:

v = u + at

u = 4.30 m/s

a = 3 m/s^2

t = 5 s

v = 4.30 + (3)(5)

v = 4.30 + 15

v = 19.30 m/s

Explanation:

Hope this helps!

5 0

3 years ago

A 100.0-kg bakery sign hangs from two thin cables as shown.

harina [27]

Answer:

1. T₁ = 500 N

2. T₂ = 866 N

Explanation:

Please see attached photo for the diagram.

Thus, we can obtain obtained the value of T₁ and T₂ as follow:

1. Determination of T₁

Angle θ = 30

Hypothenus = 100 kg

Opposite = T₁ =?

Sine θ = Opposite /Hypothenus

Sine 30 = T₁ / 100

Cross multiply

T₁ = 100 × Sine 30

T₁ = 100 × 0.5

T₁ = 50 Kg

Multiply by 10 to express in Newton

T₁ = 50 × 10

T₁ = 500 N

2. Determination of T₂

Angle θ = 60

Hypothenus = 100 kg

Opposite = T₂ = ?

Sine θ = Opposite /Hypothenus

Sine 60 = T₂ / 100

Cross multiply

T₂ = 100 × Sine 60

T₂ = 100 × 0.8660

T₂ = 86.6 Kg

Multiply by 10 to express in Newton

T₂ = 86.6 × 10

T₂ = 866 N

5 0

3 years ago

Tycho's major contribution to astronomy was ___________________?

Rina8888 [55]

Answer:

He is known primarily for being one of the people who worked to overturn the widespread belief that our universe orbits geocentrically in favor of a heliocentric model.

Explanation:

4 0

3 years ago

Calculate the total energy of 4.0 kg object moving horizontally at 20 m/s 50 meters above the surface.

Serhud [2]

Answer:

Correct answer: E total = 2,800 J

Explanation:

Given:

m = 4 kg the mass of the object

V = 20 m/s the speed (velocity) of the object

H = 50 m the height of the object above the surface

E total = ? J

The total energy of an object is equal to the sum of potential and kinetic energy

E total = Ep + Ek

Ep = m g H we take g = 10 m/s²

Ep = 4 · 10 · 50 = 2,000 J

Ek = m V² / 2

Ek = 4 · 20² / 2 = 2 · 400 = 800 J

E total = 2,000 + 800 = 2,800 J

E total = 2,800 J

God is with you!!!

4 0

3 years ago