The best conclusion that can be drawn is that D) A current does not flow in the wire
Ω₀ = the initial angular velocity (from rest)
t = 0.9 s, time for a revolution
θ = 2π rad, the angular distance traveled
Let
α = the angular acceleration
ω = the final angular velocity
The angular rotation obeys the equation
(1/2)*(α rad/s²)*(0.9 s)² = (2π rad)
α = 15.514 rad/s²
The final angular velocity is
ω = (15.514 rad/s²)*(0.9 s) = 13.963 rad/s
If the thrower's arm is r meters long, the tangential velocity of release will be
v = 13.963r m/s
Answer: 13.963 rad/s
Answer:
<em>v=40 m/s south</em>
Explanation:
<u>Momentum
</u>
It's a physical magnitude that measures the product of the mass by the velocity of a particle. Its units in the International System is kg.m/s and the formula is
Where m is the mass and v the velocity of the particle. If we wanted to solve for v, we have
The baseball has a momentum of 6.0 kg.m/s south and mass of 0.15kg, thus
The velocity is directed to the south
Answer:
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Explanation:
Answer:
Expression of work done is
Work done to move the sled is given as 187.2 J
Explanation:
As we know that the formula of work done is given as
here we know that
F = 12.6 N
d = 15.4 m
so we will have
