Answer:
A) ultraviolet light ---> violet light ----> red light-----> infrared light
Explanation:
We know that the electromagnetic spectrum with the wavelength from least to greatest is (also refer attachment)
- gamma ray
- X- rays
- Ultra-violet
- Visible
Violet
Indigo
Blue
Green
Yellow
Orange
Red
Hence the relative order of wavelengths from least to greatest in the electromagnetic spectrum is
A) ultraviolet light ---> violet light ----> red light-----> infrared light
Centre of Mass then axis of rotation and then moment of inertia. This was the toughest question for your level... happy to help ^_^. It was purely experimental question.
There could be many different comparison features that would
lead to an observation of similarity or dis-similarity.
A mirror might be said to be similar to a convex lens if it is round,
or if it has a curved surface, or if it is made of glass.
Answer:
Momentum (P)= 3.15Kg.m/s
Explanation:
Because momentum by definition is the product of mass and velocity, therefore, it's calculated by the formula;
P=mv,,,
where 'P' Is the momentum
'm' is mass in Kilograms, note that mass should be in Kilograms, therefore the 450grams should be converted to kilograms by dividing it with a 1000, i.e (450g×1kg/1000g)= 0.45kg, and now you can substitute in the formula because you have everything you need to find momentum in the right si units.
so P=mv
P=0.45Kg×7m/s
P=3.15Kg.m/s
1) Focal length
We can find the focal length of the mirror by using the mirror equation:

(1)
where
f is the focal length

is the distance of the object from the mirror

is the distance of the image from the mirror
In this case,

, while

(the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:

from which we find

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.
3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.
4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is: