−20 ≤ 59(F−32) ≤ −15

1 answer:

7 0

We take the value of F in the inequality by taking the inequalities in group. Let the first group be:

(1) -20 ≤ 59(F - 32)

Then, the second group would be,
(2) 59(F - 32) ≤ - 15

Calculating for the values of F,

(1) -20 ≤ 59F - 1888
1888 - 20 ≤ 59F
1868 ≤ 59F
F ≥ 31.66

(2) (59)(F - 32) ≤ - 15
59F - 1888 ≤ -15
59F ≤ 1873
F ≤ 31.75

The values of F are therefore,
31.66 ≤ F ≤ 31.75

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HELP PLEASE must show work I have the answer just need to show work

Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) $8+6x^4$

here we can see, both numbers are divisible by 2, so taking 2 common

$=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)$

It cannot be further simplified because both number donot have same bases.

3. $4n^9 + 12 n$

We can take 4n common

$=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)$

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. $12n^5 + 16n^3$

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

$4n^3( 3n^2 + 4)$

9. $5k^2 - 40k+10$

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

$=5(k^2 - 8k + 2)$

11. $-60 + 60n^2 +50n^3$

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

$=10(-6 + 6n^2 +5n^3)$

13. $-36n^3 -12n-28$

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

$=-4(9n^3 + 3n +7)$

15. $63n^3+81n+18$

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

$=9(7n^3 + 9n + 2)$