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Sonja [21]
3 years ago
6

−20 ≤ 59(F−32) ≤ −15

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
We take the value of F in the inequality by taking the inequalities in group. Let the first group be:

(1)    -20 ≤ 59(F - 32)

Then, the second group would be,
(2)     59(F - 32) ≤ - 15

Calculating for the values of F,

(1)     -20 ≤ 59F - 1888
          1888 - 20 ≤ 59F
              1868 ≤ 59F
                 F ≥ 31.66

(2)     (59)(F - 32) ≤ - 15
             59F - 1888 ≤ -15
             59F ≤ 1873
                F ≤ 31.75

The values of F are therefore,
               31.66 ≤ F ≤ 31.75

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Step-by-step explanation:

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the values of the series are evaluated by substituting the corresponding values of k into the equation.

\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\

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Therefore, 4 students correspond to 20% of 20 students in total.

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