Question

At the base of a frictionless icy hill that rises at 25.0∘ above the horizontal, a toboggan has a speed of 11.5 m/s toward the hill. How high vertically above the base will it go before stopping?

Answer 1

Answer:

7.2m

Explanation:

we know that energy is always conserved energy can neither be created nor be destroyed it can only be changed from one form to another form here kinetic energy is changed into potential energy with the help of energy balance equation we can find the height

from energy conservation

$\frac{1}{2}$ ×m×$v^{2}$=mgh

from both side m will be cancel out

h=$\frac{v^2}{2g}$=$\frac{12^2}{20}$

=7.2m