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3 years ago

Is the temperature at which a substance melts the same as the temperature changes from a liquid to a solid

Chemistry

1 answer:

sasho [114]3 years ago

8 0

Answer:

No.

Explanation:

If the temperature changes a substance from it's original form, going from solid to liquid, then the temperature required to change it from a liquid to a solid are the opposite. For example, Ice is Water (H2O) in it's solid form. In order to freeze water into ice, the temperature must be very low. In order to melt the ice back into water, the temperature must be higher than the freezing point, but not too high or it will boil, making it a gaseous substance instead.

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An object has a density of 10.00 g/mL. If the object has a volume of<br> 25.00 ml, what is the mass?

SVEN [57.7K]

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of object = 25 mL

Density = 10 g/mL

The mass of the object is

mass = 25 × 10

We have the final answer as

Hope this helps you

6 0

4 years ago

At the end of mitosis the cells produced are identical to each other is it True or False

My name is Ann [436]

True:

The result is two genetically identical daughter nuclei.

6 0

3 years ago

Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol

ki77a [65]

<span>

</span> $Cu_4(OH)_6(SO_4)$
<span>
You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = $\frac{2}{3} \times 2.3 \times 10^{-6}$

$= 1.53 \times 10^{-6} 
$

6 0

4 years ago

1. An oxide of chromium is found to have the following % composition: 68.4% Cr

abruzzese [7]

Answer:

Empirical formula is Cr₂O₃.

Explanation:

Given data:

Percentage of Cr = 68.4%

Percentage of O = 31.6%

Empirical formula = ?

Solution:

Number of gram atoms of Cr = 68.4 / 52 = 1.3 2

Number of gram atoms of O = 31.6 / 16 = 1.98

Atomic ratio:

Cr : O

1.32/1.32 : 1.98/1.32

1 : 1.5

Cr : O = 1 : 1.5

Cr : O = 2(1 : 1.5)

Empirical formula is Cr₂O₃.

6 0

3 years ago

Name the following Compound: CrF2

pav-90 [236]

Chromium(II) fluoride

8 0

3 years ago